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agasfer [191]
3 years ago
11

Select the ordered pairs that are on the x-axis. Choose all that apply.

Mathematics
2 answers:
ZanzabumX [31]3 years ago
6 0
-4,0 
2,0
both are true because they do not have a y coordinate, meaning they dont move off of the x-axis
cupoosta [38]3 years ago
5 0
Points are expressed in (x,y) format so any point which has a y value of zero lies upon the x axis.  So any point (x,0) is on the x axis.  In this case it would be the points:

(-4,0) and (2,0)
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Xelga [282]
The answer is $162 you take the prices of what she bought and add them together which is $73+$38+$64=$180
then you subtract the $180 from $342 which is $342-$180=$162
so the answer is $162

342 - 180 = 162
5 0
3 years ago
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This dot plot is not symmetric, and the data set has two extreme values.What is the best measure of center for this dot plot? Th
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Step-by-step explanation:

I don't know sorry....

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3 years ago
The school that Mike goes to is selling tickets to a play. On the first day of ticket sales the school sold 11 senior citizen ti
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Answer:

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Step-by-step explanation:

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2 years ago
(1 point) Linear System - Three Variables Solve the following system of equations using Gaussian elimination method. If there ar
EastWind [94]

Answer:

x=\frac{-363}{70} ≈ -5.1857

y=\frac{-192}{35} ≈ -5.4857

z=\frac{313}{84} ≈ 3.7262

Step-by-step explanation:

Rewrite the equation system as:

6x+8y=-75

-3x+6y+6z=5

2x-9y=39

Now, write the system in its augmented matrix form:

\left[\begin{array}{cccc}6&8&0&-75\\-3&6&6&5\\2&-9&0&39\end{array}\right]

applying row reduction process to  its associated augmented matrix:

Swap R1 and R3, and then Swap R1 and R2:

\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\6&8&0&-75\end{array}\right]

R3+2R1

\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\0&20&12&-65\end{array}\right]

3R2+2R1

\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&20&12&-65\end{array}\right]

15R3+20R2

\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&0&420&1565\end{array}\right]

Now we have a simplified system:

-3x+6y+6z=5\\0-15y+12z=127\\0+0+420z=1565

-3x+6y+6z=5\hspace{5 mm}(1)\\0-15y+12z=127\hspace{3 mm}(2)\\0+0+420z=1565\hspace{3 mm}(3)

From (3):

z=\frac{313}{84} (4)

Replacing (4) in (2)

y=\frac{-192}{35} (5)

Finally replacing (5) and (4) in (1)

x=\frac{-363}{70}

7 0
3 years ago
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murzikaleks [220]

Answer:

answer this 5-y this the answer thanks for

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