Answer:
The number of children (n) that can attend the birthday party can be expressed as;
n≤8
Step-by-step explanation:
Step 1
We can use the expression below to calculate the total cost of the party as shown;
C≥F+(V×n)
where;
C=total cost of Gina is willing to spend
F=fixed cost for the rent
V=cost per child
n=number of children at the party
In our case;
C=$100
F=$50
V=$6.25
n=n
replacing;
100≥50+(6.25×n)
6.25 n+50≤100
6.25 n≤100-50
6.25 n≤50
n≤50/6.25
n≤8
The number of children (n) that can attend the birthday party can be expressed as;
n≤8
Answer:
2/7
Step-by-step explanation:
There are 22 (12 + 10) total students in the class. That means that the chance of the first student picked being a girl is 12/22.
Now, we must calculate the chance of the next student to be picked <em>also </em>being a girl - however, there is a trap here! Remember that since a girl has been picked, the total student pool has decreased to 21 and and the total number of girls has decreased to 11. This means the new chance of girl being picked is 11/21.
To find the probability of both these events happening in conjunction, these fractions must be multiplied. 12/22 * 11/21 = 132/462, which simplifies to 2/7.
Answer:
$475
Step-by-step explanation:
There are 3 possible accident in this question
3% chance of losing $2000
0.1% chance of losing $150,000
96.9% chance of losing $0
Then the expected value that you will lose is:
3%* $2000 + (0.1% * $15000) + (96.9% * $0)= $75
Profit made by subtracting the price with the lose. If the company want average profit $400, the charge should be:
average profit = premium price - average lose
premium price= average profit + average lose
premium price= $400 + $75 = $475
Sorry...I dont understand......