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3 years ago

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Taxi A charges $0.20 per mile and an initial fee of $4. Taxi B charges $0.40 per mile and an initial fee of $2. Write an inequal

ity that can determine when the cost of Taxi B will be greater than Taxi A. A) 0.20x + 4 > 0.40x + 2 B) 0.20x + 4 < 0.40x + 2 C) 0.20x + 0.40x > 4 + 2 D) 0.20x + 0.40x < 4 + 2

2 answers:

makkiz [27]3 years ago

8 0

The expression for the cost of Taxi B is 0.40<em>x</em> + 2.<em> </em>The expression for the cost of Taxi A is 0.20<em>x</em> + 4. The inequality asks for when the cost of Taxi B will be greater than Taxi A, so you write it as 0.40<em>x </em>+ 2 > 0.20<em>x</em> + 4, or 0.20<em>x</em> + 4 < 0.40<em>x </em>+ 2.

The answer is B) 0.20<em>x</em> + 4 < 0.40<em>x </em>+ 2.

NARA [144]3 years ago

3 0

Answer: B. $0.20x+4$

Step-by-step explanation:

let x denotes the number of mile taxi runs.

Given : Taxi A charges $0.20 per mile and an initial fee of $4.

i.e. the expression to show total charge by Taxi A will be : $0.20x+4$

Taxi B charges $0.40 per mile and an initial fee of $2.

i.e. the expression to show total charge by Taxi B will be : $0.40x+2$

Now, the inequality that can determine when the cost of Taxi B will be greater than Taxi A will be :-

$0.20x+4$

Hence, B is the correct answer.

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