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3 years ago

PLEASE HURRY I NEED HELP ON MY EXAM! 15PTS!

Mathematics

1 answer:

Wittaler [7]3 years ago

3 0

Answer:

I III and IV

Step-by-step explanation:

It cant be All four since yeah but im really sure that what i put is the answer

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alexgriva [62]

Answer:

hon you never asked a question or added an image. id be happy to try and help if you do!

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2 years ago

Read 2 more answers

What is 1/3 of eleven sixteenth

TiliK225 [7]

It’s 5 1/3 because 16 divided by 3 is 5 1/3

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3 years ago

Determine the slope of the line that passes through the points (-4, 6) and (0,4).

gavmur [86]

Answer:

B.) $m=-\frac{1}{2}$

Step-by-step explanation:

use the slope rule

$\frac{rise}{run} \\\\\\frac{y2-y1}{x2-x1}$

Fill in values

$\frac{4-6}{0-(-4)}$

Simplify

$\frac{-2}{4}\\-\frac{2}{4}$

Simplify further

$m=-\frac{1}{2}$

Done.

3 0

3 years ago

Read 2 more answers

Factor completely. <br> <img src="https://tex.z-dn.net/?f=x%5E%7B8%7D-%5Cfrac%7B1%7D%7B81%7D" id="TexFormula1" title="x^{8}-\fra

Eduardwww [97]

We have 3⁴ = 81, so we can factorize this as a difference of squares twice:

$x^8 - \dfrac1{81} = \left(x^2\right)^4 - \left(\dfrac13\right)^4 \\\\ x^8 - \dfrac1{81} = \left(\left(x^2\right)^2 - \left(\dfrac13\right)^2\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)$

Depending on the precise definition of "completely" in this context, you can go a bit further and factorize $x^2-\frac13$ as yet another difference of squares:

$x^2 - \dfrac13 = x^2 - \left(\dfrac1{\sqrt3}\right)^2 = \left(x-\dfrac1{\sqrt3}\right)\left(x+\dfrac1{\sqrt3}\right)$

And if you're working over the field of complex numbers, you can go even further. For instance,

$x^4 + \dfrac19 = \left(x^2\right)^2 - \left(i\dfrac13\right)^2 = \left(x^2 - i\dfrac13\right) \left(x^2 + i\dfrac13\right)$

But I think you'd be fine stopping at the first result,

$x^8 - \dfrac1{81} = \boxed{\left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)}$

6 0

3 years ago

Identify a set of parallel lines and a set of perpendicular lines in this image. Please help

ddd [48]

Answer:

line AB and line CD are parallel

line AB and line EF are perpendicular

Step-by-step explanation:

it is the third option

4 0

2 years ago