PLEASE HURRY I NEED HELP ON MY EXAM! 15PTS!

Mathematics

1 answer:

Wittaler [7]3 years ago

3 0

Answer:

I III and IV

Step-by-step explanation:

It cant be All four since yeah but im really sure that what i put is the answer

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You and your friend are selling tickets to a charity event. You sell 11 adult tickets and 8 student tickets for $158. Your frien

Crazy boy [7]

{11X+8Y=158
{5X+17Y=152

{55X+40Y=790
-
{55X+187Y=1672

147Y=882
Y=6
Cost of the ticket for student is $6

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4 years ago

Please help lol!!!!!!!

Elena L [17]

Answer:

That would be 4x - 3y + 5

Step-by-step explanation:

Hope this helps

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3 years ago

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F(x)=2x^2+1 using the derivate definition

morpeh [17]

$\bf \stackrel{\textit{de} \textit{finition of a derivative as a limit}}{\lim\limits_{h\to 0}~\cfrac{f(x+h)-f(x)}{h}}\\\\
-------------------------------\\\\
f(x)=2x^2+1\implies \lim\limits_{h\to 0}~\cfrac{[2(x+h)^2+1]~~-~~[2x^2+1]}{h}
\\\\\\
\lim\limits_{h\to 0}~\cfrac{[2(x^2+2xh+h^2)+1]~~-~~[2x^2+1]}{h}
\\\\\\
\lim\limits_{h\to 0}~\cfrac{[2x^2+4xh+2h^2+1]~~-~~[2x^2+1]}{h}$

$\bf \lim\limits_{h\to 0}~\cfrac{\underline{2x^2}+4xh+2h^2\underline{+1}~~~~\underline{-2x^2-1}}{h}\implies \lim\limits_{h\to 0}~\cfrac{4xh+2h^2}{h}
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\lim\limits_{h\to 0}~\cfrac{2\underline{h}(2x+h)}{\underline{h}}\implies \lim\limits_{h\to 0}~2(2x+h)\implies \lim\limits_{h\to 0}~2(2x+0)\implies 4x$

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4 years ago

PLZ HELP ME. 3 questions be my angel.

denpristay [2]

53% for the first oneeee

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3 years ago

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Can anyone help me with this problem. This question is a little hard. Is anyone on to help. Can’t understand

exis [7]

Answer: It should be D if im looking at this correctly

Step-by-step explanation: