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siniylev [52]
3 years ago
5

What is the value of x?

Mathematics
1 answer:
Hitman42 [59]3 years ago
4 0

\triangle ABD\sim\triangle CAD\ \text{therefore the sides of triangles are in proportion}\\\\\dfrac{x}{12}=\dfrac{12}{27}\ \ \ |cross\ multiply\\\\27x=144\ \ \ |:27\\\\x=\dfrac{144}{27}\\\\x=\dfrac{16}{3}\\\\\boxed{\text{Answer:}\ B.\ \dfrac{16}{3}}

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One sample has a mean of and a second sample has a mean of . The two samples are combined into a single set of scores. What is t
Murrr4er [49]

Answer:

a) For this case we can use the definition of weighted average given by:

M = \frac{ \bar X_1 n_1 + \bar X_2 n_2}{n_1 +n_2}

And if we replace the values given we have:

M = \frac{8*4 + 16*4}{4+4}= 12

b) M = \frac{8*3 + 16*5}{3+5}= 13

c) M = \frac{8*5 + 16*3}{5+3}= 11

Step-by-step explanation:

Assuming the following question: "One sample has a mean of M=8 and a second sample has a mean of M=16 . The two samples are combined into a single set of scores.

a) What is the mean for the combined set if both of the original samples have n=4 scores "

For this case we can use the definition of weighted average given by:

M = \frac{ \bar X_1 n_1 + \bar X_2 n_2}{n_1 +n_2}

And if we replace the values given we have:

M = \frac{8*4 + 16*4}{4+4}= 12

b) what is the mean for the combined set if the first sample has n=3 and the second sample has n=5

Using the definition we have:

M = \frac{8*3 + 16*5}{3+5}= 13

c) what is the mean for the combined set if the first sample has n=5 and the second sample has n=3

Using the definition we have:

M = \frac{8*5 + 16*3}{5+3}= 11

7 0
3 years ago
Figure 1 is dilated to make fig 2
Rudik [331]

Answer:

Depening in the scale factor

Step-by-step explanation:

Figure 1 can be dilated into a bigger version that forms figure 2 or a smaller version

6 0
2 years ago
How do I solve this? Please show steps clearly so i can understand, thank you
Lesechka [4]

Answer:

The value of x=8.

Step-by-step explanation:

Given:

\frac{x+3}{x}-\frac{x+1}{x+4}=\frac{5}{x}

We need to solve this equation.

Solution:

First combining equation having same denominators we get;

\frac{x+3}{x}-\frac{5}{x}=\frac{x+1}{x+4}

Now denominators are common so we will solve the numerators we get;

\frac{x+3-5}{x}=\frac{x+1}{x+4}\\\\\frac{x-2}{x}=\frac{x+1}{x+4}

Now by cross multiplication we get;

(x-2)(x+4)=x(x+1)

Now Applying distributive property we get;

x^2+4x-2x-8=x^2+x\\\\x^2+2x-8=x^2+x

Now Combining the like terms we get;

x^2+2x-x^2-x=8\\\\x=8

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3 0
3 years ago
Draw a marble, replace it draw a second marble
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Answer:

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If θ is a first quadrant angle in standard position with P(u,v) = (3,4) evaluate cos 2 θ
zaharov [31]

We have to evaluate cos(2θ), knowing that θ is in the first quadrant and in standard position P(u,v) = (3,4).

We can picture this as:

We can write the relation:

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We now look at the identities to find cos(2θ):

\cos (2\theta)=\frac{1-\tan^2(2\theta)}{1+\tan^2(2\theta)}

There are many identities for cos(2θ), but this is expressed in the information we already know, so we can solve as:

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Answer: cos(2θ) = -7/25

8 0
1 year ago
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