Please answer quick thanks

Mathematics

1 answer:

weeeeeb [17]3 years ago

8 0

Answer:

140

Step-by-step explanation:

They are the same on both sides

<h2><em>:)Hope you enjoy this:)</em></h2>

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PLEASE HELP ME, ITS DUE RN

madam [21]

Answer:

here you go

Step-by-step explanation:

35+a+b+c=270

35+a=90

a+b=180

35+90+c=180

4 0

2 years ago

The viewing room at a planetarium is in the shape of a hemisphere. The diameter of the hemisphere is 48 feet. What is the volume

Elis [28]

A hemisphere is half a sphere.
So, the volume of a hemisphere is the half of the volume of the complete sphere.
The formula for the volume of a sphere is:
V = (4/3) π (radius)^3
Using π = 3.14 and radius = diameter / 2 = 50 feet / 2 = 25 feet.
You get:
V = (4/3) (3.14) (25 feet)^3 = 65,416.7 feet^3
Answer: 65,416.7 cu. ft.

4 0

3 years ago

Read 2 more answers

How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the

miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

$\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}$

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$\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}$

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$\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}$