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user100 [1]
2 years ago
15

Find the value of z.

Mathematics
1 answer:
AVprozaik [17]2 years ago
8 0

Answer:

  z = 110°

Step-by-step explanation:

Angles z and the one marked 70° form an linear pair, hence are supplementary.

  z = 180° -70° = 110°

<h3>Angles where chords cross</h3>

The angle made by two chords is half the sum of the arcs intercepted by those chords. Here, that means ...

  70° = 1/2(60° +x)   ⇒   x = 140° -60° = 80°

The arc w completes the circle of 360°, so we have ...

  w +x +79° +60° = 360°   ⇒   w = 360° -219° = 141°

Finally, z is the average of w and 79°:

  z = (w +79°)/2 = (141° +79°)/2 = 110° . . . as above

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Answer:

(2P + G) feet/min

Step-by-step explanation:

Speed of the panda = P

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3 years ago
Find the y-intercept of the function: f(×)=(×+10)/(×-5)​
ArbitrLikvidat [17]

Answer:

(-10,0)

Step-by-step explanation:

Hello

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4 0
3 years ago
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Darina [25.2K]

Answer:

a) Effective annual rate: 18.6%

b) Effective annual rate: 20.27%

c) Effective annual rate: 20.43%

d) Effective annual rate: 20.44%

Step-by-step explanation:

The effective annual interest rate, if it is not compounded continuously, is given by the formula

I=C(1+\frac{r}{n})^{nt}-C

where

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<em>r = nominal interest per year </em>

<em>n = compounding frequency </em>

<em>t = the length of time the interest is applied. In this case, 1 year. </em>

In the special case the interest rate is compounded continuously, the interest is given by

I=Ce^{rt}-C

(a)  Annually

I=C(1+\frac{0.186}{1})-C=C(1.186)-C=C(1.186-1)=C(0.186)

The effective annual rate is 18.6%

(b) Monthly

<em>There are 12 months in a year </em>

I=C(1+\frac{0.186}{12})^{12}-C=C(1.2027)-C=C(0.2027)

The effective annual rate is 20.27%

(c) Daily

<em>There are 365 days in a year </em>

I=C(1+\frac{0.186}{365})^{365}-C=C(1.2043)-C=C(0.2043)

The effective annual rate is 20.43%

(d)  Continuously

I=Ce^{0.186}-C=C(1.2044)-C=C(0.2044)

The effective annual rate is 20.44%

3 0
3 years ago
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Dennis_Churaev [7]

Answer:

Step-by-step explanation:

A secant is a straight line from a point outside a given circle that passes through two points on its circumference.

From the given diagram, EM and EQ are secants.

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Therefore,

\frac{EW}{WM} = \frac{EP}{PQ}   (corresponding sides of a triangle)

This implies that,

EW*PQ = EP*WM

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Answer:

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Step-by-step explanation:

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