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alexandr1967 [171]
3 years ago
15

When looking at the rational function f of x equals the quantity x minus one times the quantity x plus two times the quantity x

plus four all divided by the quantity x plus one times the quantity x minus two times the quantity x minus four, Bella and Edward have two different thoughts. Bella says that the function is defined at x = –1, x = 2, and x = 4. Edward says that the function is undefined at those x values. Who is correct? Justify your reasoning.
Mathematics
1 answer:
Sophie [7]3 years ago
3 0

\Large f(x) = \frac{(x - 1)(x + 2)(x + 4)}{(x + 1)(x - 2)(x - 4)}<span>

\Large f(x) = \frac{(x - 1)(x + 2)(x + 4)}{(x + 1)(x - 2)(x - 4)}

\Large f(x) = \frac{(x - 1)(x + 2)(x + 4)}{(x + 1)(x - 2)(x - 4)}

\Large f(x) = \frac{(x - 1)(x + 2)(x + 4)}{(x + 1)(x - 2)(x - 4)}

\Large f(x) = \frac{(x - 1)(x + 2)(x + 4)}{(x + 1)(x - 2)(x - 4)}</span>

 

Bella says that the function is defined at x = –1, x = 2, and x = 4 so Bella is wrong since the result is undefined because we cannot divide by zero Therefore, Edward is correct.

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