Answer:
The required expression is
Computation:
Let us that,
The number of shells in pile 1 be
The number of shells in pile 2 be
The number of shells in pile 3 be
Now,
The number of shells in pile 2 is 10 fewer than the number of shells in pile 1.
So, the expression is,
Step-by-step explanation:
Hope this helps :D
Multiply 15 x 3.14. You'll get 47.1. Thats the area
Answer:
a) for all values of x that are in the domains of f and g.
b) for all values of x that are in the domains of f and g.
c) for all values of x that are in the domains of f and g with g(x)≠0
Step-by-step explanation:
a) By definition (f+g)(x)=f(x)+g(x). Then x must be in the domain of f and g.
b) By definition (fg)(x)=f(x)g(x). Then x must be in the domain of f and g.
c) By definition (f/g)(x)=f(x)/g(x). Then x must be in the domain of f and g and g(x) must be different of 0.
(x-1)(x-1)
=x^2-x-x+1
=x^2-2x+1
(x+7)(x-7)
=x^2-7x+7x-49
=x^2-49
Answer: 8 1/3 yards per second
500 yards/60 seconds=8 1/3 yards per second
Check Work:
8 1/3 yards per second*60 seconds=500 yards per minute.
Hope this helps!