3 years ago

Y=6x^-4, if x is halved what happens to y?

1 answer:

5 0

X^-m=1/(x^m)
y=6/(x^4) is the equation
if x is halves
replace x with x/2
y=6/((x/2)^4)
y=6/((x^4)/16)
y=6/((x^4)(1/16))
y=((6)(16))/(x^4)
y=16(6/(x^4))

y increases by 16 times

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Step-by-step explanation:

we have:

$\tan(a) + \tan(b) + \tan(c) \\ = \tan(a) + \tan(b) - \tan(a + b) \\ = \tan( a) + \tan(b) - \frac{ \tan(a) + \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{ ( \tan(a) + \tan(b) ) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (1)$

we also have:

$\tan(a) \tan(b) \tan(c) \\ = - \tan(a) \tan(b) \tan(a + b) \\ = \frac{ -(\tan( a ) + \tan(b) ) \tan(a) \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{( \tan(a) + \tan(b)) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (2)$