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MrMuchimi
3 years ago
12

jessica weighs x+34 pounds and Ronda weighs 12 pounds less. If Jessica gains 5 pounds and Ronda loses 2 pounds, what is the sum

of their new heights.
Mathematics
1 answer:
Vladimir [108]3 years ago
8 0

Answer:

2x+59.

Step-by-step explanation:

Let <em>J </em>represent Jessica's weight and <em>R</em> represent Ronda's weight.

Jessica weighs <em>x+34</em> pounds. Thus:

J=x+34

Ronda weighs 12 pounds less than Jessica. In other words:

R=J-12=(x+34)-12\\R=x+22

The sum of their weights, therefore, is:

J+R\\=(x+34)+(x+22)=2x+56

Now, if Jessica gains 5 pounds and Ronda loses 2 pounds, the net gain of the total weight would be 3 pounds. Thus, we only need to add 3 to the original total to find the sum of their new weights:

2x+56+3=2x+59

The sum of the new [weights] is represented by 2x+59.

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Step-by-step explanation:

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snow_tiger [21]

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2 years ago
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masha68 [24]
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3 years ago
Read 2 more answers
Solve for x, 0 ≤ x ≤2π (2cosx-1)(2sinx+√3 ) = 0
vladimir1956 [14]

Answer:

x = π/3, x = 5π/3, x = 4π/3

Step-by-step explanation:

Let's split the given equation (2cosx-1)(2sinx+√3 ) = 0 into two parts, and solve each separately. These parts would be 2cos(x) - 1 = 0, and 2sin(x) + √3  = 0.

2\cos \left(x\right)-1=0,\\2\cos \left(x\right)=1,\\\cos \left(x\right)=\frac{1}{2}

Remember that the general solutions for cos(x) = 1/2 are x = π/3 + 2πn and x = 5π/3 + 2πn. In this case we are given the interval 0 ≤ x ≤2π, and therefore x = π/3, and x = 5π/3.

Similarly:

\:2\sin \left(x\right)+\sqrt{3}=0,\\2\sin \left(x\right)=-\sqrt{3},\\\sin \left(x\right)=-\frac{\sqrt{3}}{2}

The general solutions for sin(x) = - √3/2 are x = 4π/3 + 2πn and x = 5π/3 + 2πn. Therefore x = 4π/3 and x = 5π/3 in this case.

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Step-by-step explanation:

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