Answer:
To my knowledge of congruency, I would say the answer is A,
Step-by-step explanation:
Hope this helped!!!
Given:
The function is:

To find:
The domain of the given function.
Solution:
Domain is the set of input values.
We have,

It is a quadratic polynomial.
We know that a quadratic polynomial is defined for all real values of x. So, the given function is defined for all real values of x and the domain of the given function is:
Domain = Set of all real number
Domain = (-∞,∞)
Therefore, the correct option is B.
Skier one will have more potential energy
Answer:
x = π/3, x = 5π/3, x = 4π/3
Step-by-step explanation:
Let's split the given equation (2cosx-1)(2sinx+√3 ) = 0 into two parts, and solve each separately. These parts would be 2cos(x) - 1 = 0, and 2sin(x) + √3 = 0.

Remember that the general solutions for cos(x) = 1/2 are x = π/3 + 2πn and x = 5π/3 + 2πn. In this case we are given the interval 0 ≤ x ≤2π, and therefore x = π/3, and x = 5π/3.
Similarly:

The general solutions for sin(x) = - √3/2 are x = 4π/3 + 2πn and x = 5π/3 + 2πn. Therefore x = 4π/3 and x = 5π/3 in this case.
So we have x = π/3, x = 5π/3, and x = 4π/3 as our solutions.
Step-by-step explanation:
you don't show us the choices.
anyway, the real graph must be similar to the one you are showing, as it goes to - and + infinity for x = 2.
because the denominator "x-2" will be 0 for x = 2.
but the horizontal limits are both y = +3 (and not 0).
because (3x-2)/(x-2) goes more and more to 3/1 the larger (or smaller in the - direction) x gets.