A. the answer is 6x^2+9x-42
Answer:
The required point is P(-7,
) where, x-coordinate twice the y-coordinate on line 2x - 6y = 7
Step-by-step explanation:
Given equation of line is 2x-6y=7
To find point on graph whose x-coordinate twice the y-coordinate:
Let y be y-coordinate of point
Hence, x-coordinate of point will be 2y
The required point is P(2y,y) on equation of line 2x-6y=7
Now,
2x-6y=7
2(2y)-6y=7
-2y=7
y=
Thus,
The required point is P(-7,
)
Note: Figure show equation of line red line and point P as blue dot.
Answer:
the asymptote would be zero because the graph is approaching zero, but never actually touches it.
10 windows : divide 40/5=8
Then divide 80/8 =10
77.2%
To find the probably and at least on you must find the probability of none and subtract from one.
The probability of none can be found like so:
(5+6 over 5+6+7)^3 = .228
1 - .228 = .772
Hope this helps!