Answer:
y = cot(x - ⅓π) + 2
Step-by-step explanation:
The general equation for a cotangent function with the given properties is
y = Acot(Bx + C) + D, where
A = the stretching factor
π/|B| = the period
C = the phase shift (negative is to the right)
D = the vertical shift
A = 1
π/|B| = π, so1/|B| = 1 and B = 1
C = -⅓π
D = 2
The function is
y = cot(x - ⅓π) + 2
The figure below shows the graph of the function with the given parameters.
Note that the parent function y = cot(x) has the y-axis as an asymptote, so we can measure the phase shift by the movement of the asymptote π units to the right.
This was very complex, but I do believe the answer is g=1/2*pi*w^3*A
2
HAPPY NEW YEAR!
hope this helped
I believe you solved for x, but did not plug it back into 7x-35 to get that segment’s length. The correct answer is 49.
Perimeter of the ΔJKL is 48 cm
Solution:
Given 
.
RS = 8 cm and JK = 12 cm
Perimeter of 
= 32 cm
Let us find the perimeter of 
.
<u>Property of similarity triangles:</u>
If two triangles are similar, then the ratio of their perimeters is equal to the ratio of their corresponding sides.
Do cross multiplication.
Divide both sides of the equation by 8.
Hence perimeter of the ΔJKL is 48 cm.
Answer:
$2.30 for each jump rope.
Step-by-step explanation:
6.90 / 3 = 2.3
