We have been given that

Now, we need to find an ordered pair that must be on the graph of

On substituting x=0 in the above equation, we get

Therefore, the required ordered pair is given by (0,-1)
Answer:
Addition, 83.6
Step-by-step explanation:
x - 72.6 = 11, x = 83.6
The grandson must add 72.6 to both sides to solve for x.
Answer: -1/5
Step-by-step explanation:
14/20 - 81/90=
7/10-9/10= ==> 10 is the GCF of 20 and 90
(7-9)/10=
-2/10=-1/5
Answer: √y
<u>Step-by-step explanation:</u>
![\sqrt[6]{y^3}=y^{\frac{3}{6}}=y^{\frac{1}{2}}=\boxed{\sqrt y}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7By%5E3%7D%3Dy%5E%7B%5Cfrac%7B3%7D%7B6%7D%7D%3Dy%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%3D%5Cboxed%7B%5Csqrt%20y%7D)
So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

Next, square both sides:

Next, subtract x and add 2 to both sides of the equation:

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

Now you can rewrite the equation as 
Now, apply the Zero Product Property and solve for x as such:

Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:

Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>