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lara31 [8.8K]
3 years ago
9

A science fair poster is a rectangle 48 inches long and 24inches wide. What is the area of the poster in square feet?

Mathematics
1 answer:
fomenos3 years ago
7 0

Answer:

7.9936 Square feet

Step-by-step explanation:

To get the area of the poster in square feet, it might be important to convert the original dimensions in inches to feet.

1 inch = 0.0833 feet

48 inches = 48 * 0.0833 = 3.9984

24 inches = 24 * 0.0833 = 1.9992

The area of the poster in square feet is thus : 3.9984 * 1.9992 = 7.9936 square feet

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What are the next three terms of the geometric sequence 32, -16, 8, …?
MrRa [10]

Answer:

-4, 2, -1

Step-by-step explanation:

everything is being multiplied by -1/2

32 × -1/2 = -16

-16 × -1/2 = 8

So 8 × -1/2 = -4

8 0
3 years ago
What's greater then 3/8 or 2/4
iVinArrow [24]
Convert 2/4 to 4/8 and then look at the numerators. since 4 is greater than 3, 2/4 is greater than 3/8
7 0
3 years ago
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What is the correct answer..
solong [7]

Answer:

64 feet

Step-by-step explanation:

To find the height of the kite we use sin trigonometric ratio.

Let the height of the kite from the ground be x feet.

\therefore \: \sin 40 \degree =  \frac{x}{100}  \\  \\  \therefore \: 0.6427876097=  \frac{x}{100}  \\  \\ \therefore \: 0.6427876097 \times 100= x \\  \\  \therefore \:x = 64.29  \\  \\  \therefore \:x = 64 \: feet

3 0
3 years ago
Someone ask me to solve this.
Semenov [28]
X=2h, y=3k

Substitute these values into equations.

y+2x = 4 ------> 3k+2*2h=4 ----->  3k +4h =4

2/y - 3/2x = 1-----> 2/3k -3/(2*2h) = 1 ------> 2/3k - 3/4h =1

We have a system of equations now.

 3k +4h =4          ------> 3k = 4-4h ( Substitute 3k in the 2nd equation.)
2/3k - 3/4h =1

2/(4-4h) -3/4h = 1
2/(2(2-2h)) - 3/4h = 1
1/(2-2h) -3/4h - 1=0

4h/4h(2-2h) -3(2-2h)/4h(2-2h) - 4h(2-2h)/4h(2-2h) =0

(4h- 3(2-2h) - 4h(2-2h))/4h(2-2h) = 0
Numerator should be = 0
4h- 3(2-2h) - 4h(2-2h)=0

Denominator cannot be = 0
4h(2-2h)≠0

Solve equation for numerator=0
4h- 3(2-2h) - 4h(2-2h)=0
4h - 6+6h-8h+8h² =0
8h² +2h -6=0
4h² + h-3 =0
(4h-3)(h+1)=0
4h-3=0, h+1=0
h=3/4  or h=-1

Check which
4h(2-2h)≠0
1) h= 3/4  , 4*3/4(2-2*3/4)=3*(2-6)= -12 ≠0, so we can use h= 3/4
2)h=-1, 4(-1)(2-2*(-1)) =-4*4=-16 ≠0, so we can use h= -1, also.

h=3/4, then  3k = 4-4*3/4 =4 - 3=1 , 3k =1, k=1/3
h=-1, then  3k = 4-4*(-1) =8 , 3k=8, k=8/3 

So,
if h=3/4, then  k=1/3,
and if h=-1, then  k=8/3 .




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