A PDF must be put into an external program after being exported to be edited, you can't make direct changes to it. This eliminates answer choice A.
You can print documents with other extensions besides .pdf, such as those of Word documents and such, it doesn't have to be a .pdf. This eliminates answer choice B.
Since you can't directly edit a PDF, C is a possible answer.
Files don't have to be saved as a .pdf, especially just for the first time. Whenever you save a file, first time or not, you can save it as anything, and there's no reason to have to save it as a .pdf. This eliminates answer choice D.
So the answer is C. it contains material you don't want changed.
Hope this helps!
Answer:
a good algorithm must be able to accept a set of defined input. Output: a good algorithm should be able to produce results as output, preferably solutions. Finiteness: the algorithm should have a stop after a certain number of instructions. Generality: the algorithm must apply to a set of defined inputs.Explanation:
Answer:
La cilindrada total del motor es de 1997,025 centímetros cúbicos.
Explanation:
Para determinar la cilindrada total Vt en un motor de 4 cilindros de 83,6 mm de diámetro por 91 mm de carrera se debe realizar el siguiente cálculo, sabiendo que para calcular la cilindrada de un motor se debe utilizar la fórmula ((Pi x Diámetro^2)/4) x Carrera x Número de cilindros = X:
((3.14 x 83.6^2)/4) x 91 x 4 = X
((3.14 x 6,988.96)/4) x 364 = X
(21,945.3344 / 4) x 364 = X
5,486.3336 x 364 = X
1,997,025.4304 = X
1 milímetro cúbico = 0.001 centímetro cúbico
1,997,025.4304 milímetros cúbicos = 1997.0254304000005 centímetros cúbicos
Por lo tanto, la cilindrada total del motor es de 1997,025 centímetros cúbicos.
Answer:
The answer is "Option c".
Explanation:
In the given question the device A is connected by 3 wires, contributing all of them, which also includes several connector paths. When all the wires of A are broken down, and if all of this leaves no routes that can be used. Even so, if it is done to E, it's also linked to four different routes. Its solution would've been C because its value will be the MINIMUM.