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adell [148]
3 years ago
14

Suppose a triangle has two sides of length 33 and 37 and that the angle between these two sides is 120 what is the length of the

third side of the triangle

Mathematics
1 answer:
Nutka1998 [239]3 years ago
5 0

Answer:

  60.65

Step-by-step explanation:

The Law of Cosines can help you figure this out. Call the given sides "a" and "b" and the given angle "C". Then the third side, "c" will satisfy the relation ...

  c² = a² + b² -2ab·cos(C)

  = 33² +37² -2·33·37·cos(120°) = 3679

  c = √3679 ≈ 60.65476 ≈ 60.65

The length of the third side is about 60.65 units.

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A magazine article conducted a survey of 525 people in New York City and found that 30% of the population believe that the Yanke
WINSTONCH [101]

Answer:

In this case, the 30% represents the proportion of the sample. It is a statistic that can be used to estimate a parameter of the population.

Step-by-step explanation:

In this case, the 30% represents the proportion of this specific sample (survey taken by the magazine).

It is a statistic that can be used to estimate a parameter of the population. In this case, it may be used to estimate the true proportion of "people in New York who believe that the Yankees will miss the playoffs this year".

If a new sample is taken, a new statistic will be calculated that may or may not be equal to 30%.

3 0
3 years ago
FUNDRAISING A school is raising money by selling calendars for $20 each. Mrs. Hawkins promised a party to whichever of her Engli
____ [38]

Rj, this is the solution to question 19:

• 1st period class sold 60 calendars in total

,

• 2nd period class sold 123 calendars in total

We calculate the average per week, this way:

• 1st period class sold 60/4 = 15 calendars per week

,

• 2nd period class sold 123/4 = 30.75 calendars per week

In consequence the multiplication equation that represents this situation is:

15w + 30.75w = 183, where w is the number of weeks Mrs. Hawkins' classes sold calendars.

This is the solution to question 20:

We already know the average number of calendars that 1st and 2nd period classes sold per week. Now, let's calculate the average for 3nd 4th peiod classes, this way:

• 3rd period class sold 89 calendars in total

,

• 4th period class sold 126 calendars in total

Therefore, the average is:

• 3rd period class sold 89/4 = 22.25 calendars per week

,

• 4th period class sold 126/4 = 31.5 calendars per week

Summarizing, we have:

15 + 30.75 + 22.25 + 31.5 = 99.5 calendars was the average number sold by all her classes in a week.

•

7 0
1 year ago
The largest prime factor of thirty-five is _____. 7 5 9 11
vichka [17]

Answer:

7

Step-by-step explanation:

Since 9 and 11 do not factor 35, they are not the answer.

5 is a factor of 35, but not the largest. So, the answer is 7.

7 0
3 years ago
Read 2 more answers
NEED HELP FAST!
mihalych1998 [28]
The answer is currently A so yep thats the answer ok
8 0
3 years ago
Read 2 more answers
4 CHALLENGE 35 toes—how<br> many<br> feet?<br> Hint Draw a picture to help.<br> How many in all?
storchak [24]
35 toes? 5 toes on each foot
35 divided by 5=7


7 feet…?
3 0
3 years ago
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