The solutions to f(x) = 64 is x = 7 and x = –7.
Solution:
Given data:
and
To find the solutions when f(x) = 64.
Both are equations of f(x), so equate the given equations, we get

Subtract 15 from both sides of the equation.


49 can be written as 7².

Taking square root on both sides of the equation, we get
x = ±7
The solutions to f(x) = 64 is x = 7 and x = –7.
Answer:
9/25
Step-by-step explanation:
Option B) 37.12 is the right answer
Step-by-step explanation:
It is given that the qudrilateral is a rectangle which means that opposite sides wil be equal and all interior angles will be 90 degrees
So
PS = 17
PQ = SR = 33
The diagonal PR will form a right-angles triangle with PR being the hypotenuse
So,
Base = SR = 33
Perpendicular = PS = 17
Hypotenuse = PR = ?
The Pythagoras theorem will be used to find the length of PR
So,

Taking square root on both sides

Rounding off to nearest 100th
PR = 37.12
Hence,
Option B) 37.12 is the right answer
Keywords: Triangle, Pythagoras theorem
Learn more about triangles at:
#LearnwithBrainly
Answer: No more than 8.8 pounds.
Step-by-step explanation: Let x be the weight that Lorrie can add to carry-on.
We are told that an airline charges an extra fee if a carry-on bag weighs more than 30 pounds. After packing, Lorrie’s carry-on weighs 21.2 pounds. The inequality that will represent the the amount of weight Lorrie can add to the carry-on without going over the 30-pound limit is:
Let us solve for x by subtracting 21.2 from both sides of our inequality.
We can see that the weight Lorrie can add to the carry-on should be less than or equal to 8.8 pounds without going over the 30 pound limit. Therefore, the weight that Lorrie can add to the carry-on should be no more than 8.8 pounds.