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2 years ago

Noel bought a 10 ounce box of cereal for $1.63 What was the cost per ounce?

Mathematics

1 answer:

Vilka [71]2 years ago

8 0

The answer that i got was .163 because i divided the 1.63 dollars total by the total ounces (10) and got .163

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44 is F) 32 square feet

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3 years ago

For what values of x and y must ABCD be a parallelogram?

n200080 [17]

Step-by-step explanation:

We know that vertically opposite angles of a parallelogram are equal .

$\angle ABC =\angle ADC\ and \ \angle BAD = \angle DAC$

⇒ $3x^{\circ}=(4x-21)^{\circ} \ and \ 3y^{\circ}=(y+78)^{\circ}$

⇒ $3x^{\circ}-4x^{\circ}=-21^{\circ} \ and \ 3y^{\circ}-y^{\circ}=78^{\circ}$

⇒ $-x^{\circ}=-21^{\circ} \ and \ 2y^{\circ}=78^{\circ}$

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3 years ago

What is the Surface area of a cylinder with a radius of 5in and height of 4in

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282.74in 2

Step-by-step explanation:

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2 years ago

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2 years ago

A 10-foot ladder is leaning against a vertical wall. If the bottom of the ladder is being pulled away from the wall at the rate

Alex777 [14]

Answer:

The area is changing at 15.75 square feet per second.

Step-by-step explanation:

The triangle between the wall, the ground, and the ladder has the following dimensions:

H: is the length of the ladder (hypotenuse) = 10 ft

B: is the distance between the wall and the ladder (base) = 6 ft

L: the length of the wall (height of the triangle) =?

dB/dt = is the variation of the base of the triangle = 9 ft/s

First, we need to find the other side of the triangle:

$H^{2} = B^{2} + L^{2}$

$L = \sqrt{H^{2} - B^{2}} = \sqrt{(10)^{2} - B^{2}} = \sqrt{100 - B^{2}}$

Now, the area (A) of the triangle is:

$A = \frac{BL}{2}$

Hence, the rate of change of the area is given by:

$\frac{dA}{dt} = \frac{1}{2}[L*\frac{dB}{dt} + B\frac{dL}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} + B\frac{d(\sqrt{100 - B^{2}})}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} - \frac{B^{2}}{(\sqrt{100 - B^{2}})}*\frac{dB}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - 6^{2}}*9 - \frac{6^{2}}{\sqrt{100 - 6^{2}}}*9]$

$\frac{dA}{dt} = 15.75 ft^{2}/s$

Therefore, the area is changing at 15.75 square feet per second.

I hope it helps you!

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3 years ago