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lions [1.4K]
3 years ago
12

Find the value of the expression 4a^4 − 2b^2 + 40 when a = 2 and b = 7

Mathematics
2 answers:
Effectus [21]3 years ago
7 0

Answer:6

Step-by-step explanation:

4(2)^4 − 2(7)^2 + 40

4(16)-2(7)^2+40

64-2(49)+40

64-98+40

-34+40

6

Flura [38]3 years ago
4 0

Answer:

6

Step-by-step explanation:

4a^4 - 2b^2 + 40

Put a = 2 and b = 7

4(2)^4 - 2(7)^2 + 40

Solve the powers first.

4(16) - 2(49) + 40

Multiply.

64 - 98 + 40

Add and subtract.

= 6

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Charles and his friends started a community group in 2008 to address problems in their neighborhood and to host civic events.
Nikitich [7]

Answer:

D. The function indicates that the group began with 40 members and is increasing in size.

Step-by-step explanation:

The graph shows that on the y-axis, which starts with 40, the values of the members are increasing in size. The line is going up and not down so it's increasing.

5 0
3 years ago
Write a rule to describe each transformation
Annette [7]

Answer:

  (x, y) → (1.5x, 1.5y)

Step-by-step explanation:

Each of the image coordinates is 1.5 times the corresponding pre-image coordinate. The transformation is a dilation by a factor of 1.5 about the origin.

Some authors use a notation like D(1.5,O) to indicate the transformation. I like the one shown above, or ...

  (x, y) → 1.5(x, y)

4 0
3 years ago
A study was conducted on the relationship between speeds of cars and gas mileage. The correlation coefficient was 0.45. Later, t
True [87]

Answer:

0.45

Step-by-step explanation:

The correlation coefficient is used to measure the relationship between how two variables change. In this question, the two variables are cars speed and gas mileage. Since the speedometers were wrong as they were 5 mph too high in a constant manner, then the correlation between how changes in speed affect gas mileage will not be changed.

For example, if we are measuring how an increase of 15 mph decreased gas mileage, we are looking at the change in speed and it is the same if we start with 75 mph and then increase speed to 90 mph, or if we start with 45 mph and then increase to 60 mph. The change in speed for both cases will remain unchanged at 10 mph.

Now, since we have seen that the change in speed remains unchanged and since correlation coefficient is a measure of the relationship between how two variables change, then the new value of the correlation coefficient will remain the same as 0.45.

8 0
3 years ago
A second particle, Q, also moves along the x-axis so that its velocity for 0 £ £t 4 is given by Q t cos 0.063 ( ) t 2 v t( ) = 4
Vladimir79 [104]

Answer:

The time interval when V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

The distance is 106.109 m

Step-by-step explanation:

The velocity of the second particle Q moving along the x-axis is :

V_{Q}(t)=45\sqrt{t} cos(0.063 \ t^2)

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.

We are also to that :

V_Q(t) \geq 60    between   0 \leq t \leq 4

The schematic free body graphical representation of the above illustration was attached in the file below and the point when V_Q(t) \geq 60  is at 4 is obtained in the parabolic curve.

So, V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

Taking the integral of the time interval in order to determine the distance; we have:

distance = \int\limits^{3.519}_{1.866} {V_Q(t)} \, dt

= \int\limits^{3.519}_{1.866} {45\sqrt{t} cos(0.063 \ t^2)} \, dt

= By using the Scientific calculator notation;

distance = 106.109 m

4 0
3 years ago
What is the equivalent expression plzz help
Firlakuza [10]
Correct answer: the first choice !
8 0
3 years ago
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