What is the total number of rabbits in the neighborhood in year 2

In a sample of students, 125 said they exercise on a regular basis. How large was the sample if 27.3% said they exercised on a r

krek1111 [17]

First, let's declare a variable

x = # of students

Now, let's create an equation to model the problem.

x * 0.273 = 125

Divide both sides by 0.273

x = 457.8 = 458 students.

Note, I rounded to the nearest whole number.

5 0

2 years ago

Read 2 more answers

(−2k 3 −7k 2 +5k)+(6k 2 +3k)=

shusha [124]

Answer: 5k +7

Step-by-step explanation: -2k + -7k + 5k is -4K and 2+3=5 -4K +5 and 6k +3k= 9k + 2 then u do -4K plus 9k and get 5k next, 5+2

7 0

2 years ago

On any given day, mail gets delivered by either Alice or Bob. If Alice delivers it, which happens with probability 1/4 , she doe

Troyanec [42]

Answer:

(a) The value of fₓ (9.5) is 0.125.

(b) The value of fₓ (10.5) is 0.50.

Step-by-step explanation:

Let X denote delivery time of the mail delivered by Alice and Y denote delivery time of the mail delivered by Bob.

It i provided that:

$X\sim U(9, 11)\\Y\sim U(10, 12)$

The probability that Alice delivers the mail is, p = 1/4.

The probability that Bob delivers the mail is, q = 3/4.

The probability density function of a Uniform distribution with parameters [a, b] is:

$f(x)=\left \{ {{\frac{1}{b-a};\ a, b>0} \atop {0;\ otherwise}} \right.$

The probability density function of the delivery time of Alice is:

$f(X_{A})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[9, 11]} \atop {0;\ otherwise}} \right.$

The probability density function of the delivery time of Bob is:

$f(X_{B})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[10, 12]} \atop {0;\ otherwise}} \right.$

(a)

Compute the value of fₓ (9.5) as follows:

For delivery time 9.5, only Alice can do the delivery because Bob delivers the mail in the time interval 10 to 12.

The value of fₓ (9.5) is:

$f_{X}(9.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times0)\\=\frac{1}{8}\\=0.125$

Thus, the value of fₓ (9.5) is 0.125.

(b)

Compute the value of fₓ (10.5) as follows:

For delivery time 10.5, both Alice and Bob can do the delivery because Alice's delivery time is in the interval 9 to 11 and that of Bob's is in the time interval 10 to 12.

The value of fₓ (10.5) is:

$f_{X}(10.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times\frac{1}{2})\\=\frac{1}{8}+\frac{3}{8}\\=0.50$

Thus, the value of fₓ (10.5) is 0.50.

5 0

3 years ago

What is the first step to simplify the expression? (1 Point)

Stells [14]

Multiply first then you would wanna add but you can't until you subtract 5-3 then add I got 12

8 0

3 years ago

Solve for x,,,3x-1/4=-5/11

Neko [114]

$\dfrac{3x-1}{4}=-\dfrac{5}{11}\ \ \ \ |cross\ multiply\\\\11(3x-1)=4\cdot(-5)\\\\33x-11=-20\ \ \ \ |add\ 11\ to\ both\ sides\\\\33x=-9\ \ \ \ |divide\ both\ sides\ by\ 33\\\\x=-\dfrac{9}{33}\\\\\boxed{x=-\dfrac{3}{11}}$

4 0

3 years ago