How do you write 10x10x10x10 using exponents?

Anyone mind helping?!

oksano4ka [1.4K]

Answer: Your answer is B

Step-by-step explanation:

Pls mark me brainiest

4 0

3 years ago

What is x+2+x^2+2 <br>what is x+2+x^2+2 <br>what is x+2+x^2+2

xxMikexx [17]

If you factor the expression, your answer would look like this:
x + x^2 + 4
If you simplify the expression, your answer would look like this:
x^2 + x + 4

7 0

4 years ago

Read 2 more answers

The sum of two numbers is -18. If the first number is 10, which equation represents this situation, and what is the second numbe

professor190 [17]

Answer:

The equation that represents this solution is: 10+x= -18

The second number is -28.

Step-by-step explanation:

To solve for this, we first need to make an equation. We know that one of the numbers, the first one, is 10, but the second is unknown. Because of this, we will label the unknown number x. We also know that the -18 is the sum, so we know it will be behind the equal sign. Using this info, we can make the following equation.

10+x= -18

We did 10 because it was the first, added it with the unknown x, and it all equals -18. This would be your equation.

To find the answer, you need to solve the equation.

10+x= -18

First, since we are adding ten to both sides, subtract ten from both sides.

10-10+x= -18-10

Now, solve. Remember that subtracting a positive number is the same as adding a negative number.

x= -28

Now, check. Does 10+ -28 equal -18? Yes, so we are correct.

6 0

3 years ago

Three out of seven students in the cafeteria line are chosen to answer survey questions. How many different combinations of thre

Hatshy [7]

Answer:

35 possible combinations would be there.

Step-by-step explanation:

We have total of seven students we have to choose three out of those seven

$^{n}C_r=\frac{n!}{r!\cdot (n-r)!}$

n is the total possibilities n =7 in the given case

And r is the chosen ones

Hence, r=3 in the given case.

Substituting the values of n and r in the formula we get

$^{7}C_3$

$\frac{7!}{3!(7-3)!}$

$\frac{7!}{3!\cdot 4!}$

Using n!=n(n-1)----1

$\frac{7\cdot 6\cdot 5\cdot 4!}{3\cdot 2\cdot 1\cdot 4!}$

Cancel the common factor we get

$35$ possible combinations would be there.

8 0

3 years ago

Nathan ordered one cheeseburger and one bag of chips for 3.75 jack ordered two cheeseburgers and three bags of chips for 8.25 kn

Elan Coil [88]

Answer:

cheeseburger is $3 and chips is $0.75

Step-by-step explanation:

Let price of cheeseburger be x while price of a bag of chips be y hence for the case of Nathan, we can write the equation as x+y=3.75. Similarly, for Jack, we can write it as 2x+3y=8.25

x+y=3.75 hence x=3.75-y and substituting this into the second equation we have

2x+3y=8.25

2(3.75-y)+3y=8.25

7.5-2y+3y=8.25

y=8.25-7.5=0.75

x=3.75-y=3.75-0.75=3

Therefore, price of cheeseburger is $3 and chips is $0.75

7 0

3 years ago