Answer:
Step-by-step explanation:
Problem A
t(1) = 2(1) + 5
t(2) = 2*2 + 5 = 9
t(3) = 2*3 + 5 = 11
t(4) = 2*4 + 5 = 13
So this is the explicit result. Now try it recursively.
t_3 = t_2 + 2
t_3 = 9 + 2
t_3 = 11 which is just what it should do.
t_n = t_(n - 1) + 2
Problem B
t(1) = 3 * 1/2
t(1) = 3/2
t(2) = 3*(1/2)^2
t(2) = 3 * 1/4
t(2) = 3/4
t(3) = 3*(1/2)^3
t(3) = 3 * 1/8
t(3) = 3/8
t(4) = 3 (1/2)^4
t(4) = 3 (1/16)
t(4) = 3/16
So in general
t_n = t_n-1 * 1/2
For example t(5)
t_5 = t_4 * 1/2
t_5 = 3 /16 * 1/2 = 3/32
We are given the following information:
<em />
<em>each person uses 3/8 a box</em>
<em>there are 6 boxes</em>
Because each box is 
, and there are 6 boxes, we know that 1 person is 
, or 
.
In order to find how many people can use the 6 boxes, we can divide it by 3 (for each use):
48 / 3 = 16
Therefore, 16 people can share the worms.
<em>Hope this helps! :)</em>
10.4. You multiply .80 times 12 and get 9.6. Then you add 9.6 to 0.80 and get 10.4
.........Phitagors theory
