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Leokris [45]
3 years ago
14

What is the emf produced in a 1.5 meter wire moving at a speed of 6.2 meters/second perpendicular to a magnetic field of strengt

h 3.96 × 10-3newtons/amp·meter?
Physics
1 answer:
Natasha2012 [34]3 years ago
3 0
General formula for emf is : emf = vBL (sin 0)...(1)
As the angle here is 90º and sin90º =1.
So, equation (1) becomes : emf = vBL Putting values :
emf = (6.2)(1.5)(3.96 * 10<span>^-3) = 0.0369 volts
</span>Hope this helps:)

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