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3 years ago

Explain the forces of that affect the soccer balls path.

Physics

1 answer:

mafiozo [28]3 years ago

5 0

Answer:

yeah its correct

Explanation:

As the ball spins, friction between the ball and air causes the air to react to the direction of spin of the ball. ... Therefore, when a soccer player kicks the ball right of center the ball spins counter-clockwise and the Magnus force acts left, causing the ball to curve left.

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Can someone help me??<br><br> A car travels 1026 km in 6 hours. Find its average speed.

tankabanditka [31]

The average speed of the car is 171.

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3 years ago

Read 2 more answers

A stretched string is 2.11 m long and has a mass of 19.5 g. When the string oscillates at 440 Hz , which is the frequency of the

blsea [12.9K]

Answer:

The tension of the string is 41.876 N

Explanation:

Given;

length of the string, L = 2.11 m

mass of the string, m = 19.5 g = 0.0195 kg

frequency of the wave, f = 440 Hz

wavelength, λ = 15.3 cm = 0.153 m

The velocity of the wave is given by;

v = fλ

v = 440 x 0.153

v = 67.32 m/s

Also the velocity of the wave is given by

$v = \sqrt{\frac{T}{\mu} }$

where;

μ is mass per unit length = 0.0195 / 2.11 = 0.00924 kg/m

T is the tension of the string

T = v²μ

T = (67.32)²(0.00924)

T = 41.876 N

Therefore, the tension of the string is 41.876 N

5 0

4 years ago

Explain the following observation referring to the appropriate process of heat transfer in each case

tigry1 [53]

If the two cups are the same/equal in all regards the spoon makes the difference in heat loss. Metal spoon is a good conductor, heat conducts up the spoon handle. Radiant and convection losses occur in the surrounding air. Metal becomes a “heat sink”.

Spoon will feel warmer to the touch than a pottery or foam cup that is not a good conductor.

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3 years ago

A 9-μC positive point charge is located at the origin and a 6 μC positive point charge is located at x = 0.00 m, y = 1.0 m. Find

sukhopar [10]

Answer:

The coordinates of the point is (0,0.55).

Explanation:

Given that,

First charge $q_{1}=9\times10^{-6}\ C$ at origin

Second charge $q_{2}=6\times10^{-6}\ C$

Second charge at point P = (0,1)

We assume that,

The net electric field between the charges is zero at mid point.

Using formula of electric field

$E=\dfrac{kq}{r^2}$

$0=\dfrac{k\times9\times10^{-6}}{d^2}+\dfrac{k\times6\times10^{-6}}{(1-d)^2}$

$\dfrac{(1-d)}{d}=\sqrt{\dfrac{6}{9}}$

$\dfrac{1}{d}=\dfrac{\sqrt{6}}{3}+1$

$\dfrac{1}{d}=1.82$

$d=\dfrac{1}{1.82}$

$d=0.55\ m$

Hence, The coordinates of the point is (0,0.55).

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3 years ago

(b) Figure 3.32 shows the orbit of a planet around the Sun. Compare the linear speed of the planet at positions X, Y and Z.

Viefleur [7K]

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4 years ago

Explain the forces of that affect the soccer balls path.​

Explain the forces of that affect the soccer balls path.