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OLEGan [10]
3 years ago
10

3. A fire truck is parked twelve feet

Mathematics
1 answer:
Firlakuza [10]3 years ago
5 0

Answer: 9.04 feet

Step-by-step explanation:

First, it is important to draw a Right triangle, as the one attached, where "x" represents the height in feet from the ground in which the fire is burning.

In this case you need to use the following Trigonometric Identity:

tan\alpha =\frac{opposite}{adjacent}

You can identify that:

\alpha=37\°\\\\ opposite=x\\\\adjacent=12

Therefore, you can substitute values into tan\alpha =\frac{opposite}{adjacent}:

tan(37\°)=\frac{x}{12}

Finally, you must solve for "x" in order to find its value. You get that this is:

12*tan(37\°)=x\\\\x=9.04

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Kelly ran 6.2 miles Monday, 10.95 miles Wednesday, and 8.25 miles on Thursday. How many miles did she run in all?
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Please help mee pleaseee
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Answer:

The exact answer in terms of radicals is x = 5*\sqrt[3]{25}

The approximate answer is x \approx 14.62009 (accurate to 5 decimal places)

===============================================

Work Shown:

Let y = \sqrt[5]{x^3}

So the equation reduces to  -7  = 8-3y

Let's solve for y

-7 = 8-3y

8-3y = -7

-3y = -7-8 ... subtract 8 from both sides

-3y = -15

y = -15/(-3) ... divide both sides by -3

y = 5

-----------

Since y = \sqrt[5]{x^3} and y = 5, this means we can equate the two expressions and solve for x

y = 5

\sqrt[5]{x^3} = 5

x^3 = 5^5 Raise both sides to the 5th power

x^3 = 3125

x = \sqrt[3]{3125} Apply cube root to both sides

x = \sqrt[3]{125*25}

x = \sqrt[3]{125}*\sqrt[3]{25}

x = \sqrt[3]{5^3}*\sqrt[3]{25}

x = 5*\sqrt[3]{25}

x \approx 14.62009

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