Answer:
c
Step-by-step explanation:
Answer: 14 x 10^9
Step-by-step explanation:
Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
________________________________
now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
Answer:
Tristan will need 32 feet of material for the perimeter of the garden.
Step-by-step explanation:
Given that
Area of square garden = A = 64 square feet
Perimeter = P = ?
We know that for calculation of perimeter, length of side of square is required which is not directly given in the question. The area will be used to calculate length of side and then length will be used to calculate the perimeter.
So,

s is for side
Putting the value of area

Taking square root on both sides

The length of side is 8 feet.
Perimeter will be:

Hence,
Tristan will need 32 feet of material for the perimeter of the garden.
ANSWER

EXPLANATION
The problem represents a geometric progression.
The general form of a geometric sequence is:

where a = first term
r = common ratio
The first term from the table is the first price (for the first month). That is $80.00
To find the common ratio, we divide a term by its preceeding term.
Let us divide the price of the second month from the first.
We have:

The price after the 8th month is the value of a(n) when n = 8
So, we have that: