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weqwewe [10]
2 years ago
9

The length of a rectangle is 5 inches more than the width . The perimeter is 70 inches . Find the length .

Mathematics
1 answer:
son4ous [18]2 years ago
3 0

Answer:

15 Inches

Step-by-step explanation:

70 divided by 5 is 15

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Help due soon will give brainliest
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Here is the answer! Hope it helps! (C.)

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Answer:

Step-by-step explanation:

Problem One

Perimeter is in meters not square meters. The equation is

2*(6.8+x) + 2*12.5= 47                Remove the brackets. Combine like terms  

13.6 + 2x + 25 = 47

38.6 + 2x = 47                            Subtract 38.5 from both sides

2x = 47 - 38.6  

2x = 8.4                                      Divide by 2

x = 4.2

Answer D

Problem 2

This problem is asking that you calculate the perimeter of a swimming pool.

The two semicircles on the ends make a whole circle.

The diameter of the semicircles is obtained from the difference of the two given lengths.

The rectangle has a length of 12. The length of the rectangle and the 2 semicircles is 16. The difference is 4. You could divide this by 2 to get the radius. I would just leave it as the diameter.

So the perimeter is pi*d + 2 * 12 [there are 2 lengths]

Perimeter = 4*pi + 24

Perimeter = 12.56 + 24

Perimeter = 36.56

Answer A

Problem 3

This is the circle inside the square.

The radius of the circle = 9

The diameter of the circle and the length of square's side = 2*9 = 18

The area of the square = s^2  where s = 18

The area of the square = 18^2 = 324

The area of the circle = pi * 9^2 = 3.24 * 81 = 251.34

The area of the Shaded area = 324 - 251.34 = 69.66

Answer C

Problem 4

b1 = 5

b2 = 11.5

h = 4.5

Formula

Area = (b1 + b2 ) * 4.5/2

Area =  (5 + 11.5) * 4.5 /2

Area = 16.5 * 4.5 / 2

Area = 74.25/2

Area = 37.125

Answer D

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3 years ago
Mr. Clark traveled 456.4 km in 14 days.
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\qquad \qquad\huge \underline{\boxed{\sf Answer}}

<h3><u>Distance travelled each day is</u> : </h3>

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<h3><u>Explanation</u> : </h3>

Distance travelled in 14 days is : 456.4 km

And if he travels same Distance each day, so let the Distance travelled on each day be x

According to question ~

\qquad \sf  \dashrightarrow \: 14 \times x = 456.4

\qquad \sf  \dashrightarrow \: x = 456.4 \div 14

\qquad \sf  \dashrightarrow x = \: 32.6  \: \: km

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