All categories

3 years ago

If infinitely many values of y satisfy the equation 2(4+cy) = 12y+8, then what is the value of c?

Mathematics

2 answers:

DanielleElmas [232]3 years ago

6 0

Answer:

c = 6

Step-by-step explanation:

Since there are an infinite number of solutions for y

Choose any value for y and substitute into the equation.

let y = 1, then

2(4 + c) = 12 + 8 = 20 ( divide both sides by 2 )

4 + c = 10 ( subtract 4 from both sides )

c = 6

Viktor [21]3 years ago

3 0

Answer:

c = 6

Step-by-step explanation:

2(4 + cy) = 12y + 8

8 + 2cy = 12y + 8

12y + 8 = 8 + 2cy

12y - 2cy = 8 - 8

2y (6 - c) = 0

Divide through by 2y

(6 - c) = 0

c = 6

You might be interested in

To paint a house, a painting company charges a flat rate of $500 for supplies, plus $50 for each hour of labor.

sattari [20]

Answer:

50x20=1000+500= 1500

50x50=2500+500=3000

Step-by-step explanation:

7 0

3 years ago

Whats a quadratic equation that has the roots of 6 and negative 9

Komok [63]

Answer:

x^2-3x-54

Step-by-step explanation:

(x+6)(x-9) Setup the roots

x^2-9x+6x-54 FOIL out the terms

x^2-3x-54 Add like terms together

5 0

3 years ago

Order the decimals from least to greatest.<br><br> 1.45, 2.56, 0.99

zvonat [6]

Answer:

0.99, 1.45 then 2.56 will be the greatest!

7 0

3 years ago

Prove the divisibility:<br><br>45^45·15^15 by 75^30

garri49 [273]

Answer:

$3^{75}$ .

Step-by-step explanation:

We have been an division problem: $\frac{45^{45}*15^{15}}{75^{30}}$ .

We will simplify our division problem using rules of exponents.

Using product rule of exponents $(a*b)^n=a^n*b^n$ we can write:

$45^{45}=(9*5)^{45}=9^{45}*5^{45}$

$15^{15}=(3*5)^{15}=3^{15}*5^{15}$

$75^{30}=(15*5)^{30}=15^{30}*5^{30}$

Substituting these values in our division problem we will get,

$\frac{9^{45}*5^{45}*3^{15}*5^{15}}{15^{30}*5^{30}}$

Using power rule of exponents $a^n*a^m=a^{n+m}$ we will get,

$\frac{9^{45}*5^{(45+15)}*3^{15}}{15^{30}*5^{30}}$

$\frac{9^{45}*5^{60}*3^{15}}{15^{30}*5^{30}}$

Using product rule of exponents $(a*b)^n=a^n*b^n$ we will get,

$\frac{(3*3)^{45}*5^{60}*3^{15}}{(3*5)^{30}*5^{30}}$

$\frac{3^{45}*3^{45}*5^{60}*3^{15}}{3^{30}*5^{30}*5^{30}}$

Using power rule of exponents $a^n*a^m=a^{n+m}$ we will get,

$\frac{3^{(45+45+15)}*5^{60}}{3^{30}*5^{(30+30)}}$

$\frac{3^{105}*5^{60}}{3^{30}*5^{60}}$

$\frac{3^{105}}{3^{30}}$

Using quotient rule of exponent $\frac{a^m}{a^n}=a^{m-n}$ we will get,

$\frac{3^{105}}{3^{30}}=3^{105-30}$

$3^{105-30}=3^{75}$

Therefore, our resulting quotient will be $3^{75}$ .

7 0

3 years ago

the length of a rectangle is 8 less than twice the width. the perimeter is 38 feet. Find the length and width. someone please he

Aleksandr-060686 [28]

Answer:L=4 W=15

Step-by-step explanation:

P=2L+2W

38-8=30

If length is 8 less than twice the width and the perimeter is 38, then subtract 38-8 which is 30, then divide 30 by 2 to get 15.

P=2(4) +2(15)

P=38

7 0

3 years ago