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dem82 [27]
4 years ago
15

H(x) = x3 + 7 Determine whether the function is one-to-one.

Mathematics
1 answer:
zubka84 [21]4 years ago
6 0

Answer:

we conclude that the function is one-to-one.

Step-by-step explanation:

A function will a one-to-one function if it

  • passes the vertical line test to make sure it is indeed a function, and
  • also a horizontal line test to make sure it is it one-to-one.

In other words,

The function will be one-to-one if it passes the vertical line test, and also if the horizontal line only cuts the graph of the function in one place.

The reason is that there must be only one x-value for each y-value.

Given the function

h\left(x\right)\:=\:x^3\:+\:7

Have a look at the attached graph.

  • The red portion represents the graph of the function h\left(x\right)\:=\:x^3\:+\:7.
  • The green portion represents the graph of x=2 which is basically a vertical line test. Vertical line indicates that it cuts the cuts the graph of the function in one place. So it is clear that h\left(x\right)\:=\:x^3\:+\:7 is indeed a function.
  • The blue line represents the graph of y=9, which is basically a horizontal line test. Horizontal line indicates that it cuts the cuts the graph of the function in one place. So it is clear that h\left(x\right)\:=\:x^3\:+\:7 is a one-to-one function, as there is only one x-value for each y-value.

Therefore, we conclude that the function is one-to-one.

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Rewrite the following differences of squares as a product of two integers. (a). 81 − 1 (b). 400 − 121
Hatshy [7]

Answer:

(a) 10×8

(b) 31×9

Step-by-step explanation:

We have given that

(a) 81 - 1

We have to write this in form of product of two integers

We know the algebraic equation a^2-b^2=(a+b)(a-b)

As 81 -1 can be written as 9^2-1^2

So 9^2-1^2=(9+1)(9-1)=10\times 8

(b) We have given 400 - 121

We have to write this in form of product of two integers

We know the algebraic equation a^2-b^2=(a+b)(a-b)

As 81 -1 can be written as {20}^2-{11}^2

So {20}^2-{11}^1=(20+11)(20-11)=31\times 9

4 0
3 years ago
Evaluate the function for <br> g (-2).<br> If g(x)= -6x+3, find g(-2).
Ivan

Answer:

Step-by-step explanation:

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cricket20 [7]
Ron’s is .55 and teddys is 1.65
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The ratio of pickles to onions on a burger was 2:4 for every blank pickles there are blank onions
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A water tank is in the shape of a right circular cone as shown above. The diameter of the cone is 10 feet, and the height is 15
Vsevolod [243]

Answer:

The rate at which the height of the water tank is changing is approximately 0.4244 ft/hour

Step-by-step explanation:

The given parameters are;

The diameter of the cone = 10 feet

The height of the cone = 15 feet

The rate at which water is leaking from the tank, (dV/dt) = 12 ft³/h

The volume of water in the tank = 27·π cubic feet

The volume V of a right circular cone with radius r and height h = 1/3×π×r²×h

The rate of change of the volume, dV, with time dt is given as follows;

The radius of the cone when the volume of the water in the tank is 27·π cubic feet is given as follows;

1/3×π×r²×h = 27·π ft³

The ratio of the height to the radius of the cone is h/r = 15/5 = 3

h/r = 3

∴ r =h/3

The volume of the cone, V = 1/3×π×r²×h = 1/3×π×(h/3)²×h = 1/27×π×h³ =  h³/27×π

dV/dt = dV/dh × dh/dt

Which gives;

12 = d(h³/27×π)/dh × dh/dt = π×h²/9 × dh/dt

dh/dt = 12/(π×h²/9)

At 27·π ft³ = 1/27×π×h³ ft³, we have;

27 = 1/27×h³

27² = h³

h = ∛27² = 9

∴ dh/dt = 12/(π×h²/9) = 12/(π×9²/9) = 12/(π×9) = 4/(3·π) ≈ 0.4244 ft/hour

The rate at which the height of the water tank is changing ≈ 0.4244 ft/hour.

6 0
3 years ago
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