When a candle burns, you can't hear the flame, and you can't light a light-bulb with it, so you know that there's no sound energy or electrical energy coming from it.
However, if you've ever actually been around a candle while it's in the act of burning, you may have noticed that you can SEE the flame, and if you put your hand close enough to it, you can FEEL the flame and even burn yourself in it. These observations indicate that while the candle is burning, the chemical energy in it is being converted to light energy and heat energy. (choice-C)
Answer:
it develop isometric strength and endurance in glutes calves quadriceps,hamstring and adductor muscle
In order to help the student expand his/her
knowledge I will help answer the question. This in hope that the student will
get a piece of knowledge that will help him/her through his/her homework or
future tests.
All of the mentioned factors determine the
amount of electric current in a circuit exept for the ammeter. The ammeter is a
measuring tool which does not affect the lfow of electric current in a circuit.
The answer is
Switch
Voltage
Resistance
<span>
I hope
it helps, Regards.</span>
<span> </span>
Answer:
The force he will apply is 666.667 N
Explanation:
The impulse is given as the product of Force and time:
Impulse (I) = F * t
As we are provided with the impulse and that is:
I = 100 ns and t = 0.15 s
So, required force is:
F = I/t
F = 100/0.15
F = 666.6667 N
Answer:
Explanation:
For this problem we use the translational equilibrium condition. Our reference frame for block 1 is one axis parallel to the plane and the other perpendicular to the plane.
X axis
-Aₓ - f_e +T = 0 (1)
Y axis
N₁ - W_y = 0 ( 2)
let's use trigonometry for the weight components
sin θ = Wₓ / W
cos θ = W_y / W
Wₓ = W sin θ
W_y = W cos θ
We write the diagram for the second body.
Note that in the block the positive direction rd upwards, therefore for block 2 the positive direction must be downwards
W₂ -T = 0 (3)
we add the equations is 1 and 3
- W₁ sin θ - μ N₁ + W₂ = 0
from equation 2
N₁ = W₁ cos θ
we substitute
-W₁ sin θ - μ (W₁ cos θ) + W₂ = 0
W₂ = m₁ g (without ea - very expensive)
This is the smallest value that supports the equilibrium system