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3 years ago

When a candle burns, which forms of energy does the chemical energy in the candle change to?

1 answer:

6 0

When a candle burns, you can't hear the flame, and you can't light a light-bulb with it, so you know that there's no sound energy or electrical energy coming from it.

However, if you've ever actually been around a candle while it's in the act of burning, you may have noticed that you can SEE the flame, and if you put your hand close enough to it, you can FEEL the flame and even burn yourself in it. These observations indicate that while the candle is burning, the chemical energy in it is being converted to light energy and heat energy. (choice-C)

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What happens to the density of a fluid as the substance gains thernal energy

Natalka [10]

Density reduces

Explanation:

The density of a fluid will reduce as a substance gains more thermal energy. Heat is a form of thermal energy usually noticed as temperature differences in a matter.

When thermal energy is gained by a body, the temperature of the body rises.
The particles of the medium gains more kinetic energy.
This causes the substance to expand and it has more volume.
When a substance expands, it occupies more space.
The more the volume a body occupies, the lesser the density.
Expansion does not change the mass of the fluid but the volume changes.
This is why density decreases.

Learn more:

Density brainly.com/question/8441651

#learnwithBrainly

8 0

3 years ago

A pendulum is formed by taking a 2kg mass and hanging it from the ceiling using a steel wire with a diameter of 1.1 mm. It is ob

Mekhanik [1.2K]

Please elaborate more on your question so I can help you

5 0

3 years ago

A concert loudspeaker suspended high off the ground emits 28.0 W of sound power. A small microphone with a 0.700 cm2 area is 55.

grandymaker [24]

Explanation:

It is known that wave intensity is the power to area ratio.

Mathematically, I = $\frac{P}{A}$

As it is given that power is 28.0 W and area is $7 \times 10^{-5} m^{2}$ .

Therefore, sound intensity will be calculated as follows.

I = $\frac{P}{A}$

= $\frac{28.0 W}{4 \times 3.14 \times 7 \times 10^{-5} m^{2}}$

= $0.318 \times 10^{5} W/m^{2}$

or, = $3.18 \times 10^{4} W/m^{2}$

Thus, we can conclude that sound intensity at the position of the microphone is $3.18 \times 10^{4} W/m^{2}$ .

7 0

3 years ago

What is the area of the bottom of a tank 30.0 cm long and 15.0 cm wide?

Igoryamba

Answer:

perimeter of the bottom of the tank is 450 cm

Explanation:

If you want to get area you need the Length, width,and height.

5 0

3 years ago

Read 2 more answers

If this energy were used to vaporize water at 100.0 ∘C, how much water (in liters) could be vaporized? The enthalpy of vaporizat

Zanzabum

Answer:

0.429 L of water

Explanation:

First to all, you are not putting the value of the energy given to vaporize water, so, to explain better this problem, I will assume a value of energy that I took in a similar exercise before, which is 970 kJ.

Now, assuming that the water density is 1 g/mL, this is the same as saying that 1 g of water = 1 mL of water

If this is true, then, we can assume that 1 kg of water = 1 L of water.

Knowing this, we have to use the expression to get energy which is:

Q = m * ΔH

Solving for m:

m = Q / ΔH

Now "m" is the mass, but in this case, the mass of water is the same as the volume, so it's not neccesary to do a unit conversion.

Before we begin with the calculation, we need to put the enthalpy of vaporization in the correct units, which would be in grams. To do that, we need the molar mass of water:

MM = 18 g/mol

The enthalpy in mass:

ΔH = 40.7 kJ/mol / 18 g/mol = 2.261 kJ/g

Finally, solving for m:

m = 970 / 2.261 = 429 g

Converting this into volume:

429 g = 429 mL

429 / 1000 = 0.429 L of water

3 0

3 years ago