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shusha [124]
2 years ago
10

A baseball pitcher throws a fastball with a 100 ns impulse. if he applied the force in 0. 15 seconds, what force did he apply?

Physics
1 answer:
Papessa [141]2 years ago
8 0

Answer:

The force he will apply is 666.667 N

Explanation:

The impulse is given as the product of Force and time:

              Impulse (I) = F * t

As we are provided with the impulse and that is:

I = 100 ns and t = 0.15 s

So, required force is:

                 F = I/t

                 F = 100/0.15

                 F = 666.6667 N

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6 0
3 years ago
I am really struggling with this question because I can't find anything on aphelion and perihelion, it's not a topic we went ove
Hoochie [10]

I have a strange hunch that there's some more material or previous work
that goes along with this question, which you haven't included here.

I can't easily find the dates of Mercury's extremes, but here's some of the
other data you're looking for:

Distance at Aphelion (point in it's orbit that's farthest from the sun):
<span><span><span><span><span>69,816,900 km
0. 466 697 AU</span>

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<span><span><span><span>46,001,200 km
0.307 499 AU</span> </span>

Perihelion and aphelion are always directly opposite each other in
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1/2 (50%) of that is  43.9845  Earth days

The average of the aphelion and perihelion distances is

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3 0
4 years ago
A material through which electrons can move easily is a what
kirill [66]

Answer:

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3 0
1 year ago
Hans Langseth's beard measured 5.33 m in 1927. Consider two charges, q1 = 2.42 nC and an unspecified charge, q2, are separated 5
schepotkina [342]

Answer:

-7.89 * 10^(-9) C

Explanation:

Parameters given:

q1 = 2.42 nC = 2.42 * 10^(-9) C

Distance between q1 and q2 = 5.33 m

q3 = 1.0 nC = 1 * 10^(-9) C

Distance between q1 and q3 = 1.9 m

Distance between q2 and q3 = 5.33 - 1.9 = 3.43 m

The net force acting on q3 is:

F = F(q1, q3) + F(q2, q3)

F = (k*q1*q3)/1.9² + (k*q2*q3)/3.43²

F = (9 * 10^(9) * 2.42 * 10^(-9) * 1 * 10^(-9))/3.61 + (9 * 10^(9) * q2 * 1 * 10^(-9))/11.7649

F = 6.033 * 10^(-9) + 0.765*q2

If the net force is zero:

0 = 6.033 * 10^(-9) + 0.765*q2

-0.765*q2 = 6.033 * 10^(-9)

=> q2 = -[6.033 * 10^(-9)]/0.765

q2 = -7.89 * 10^(-9) C

3 0
3 years ago
Explain how the meanings of the terms biotic factor and abiotic factor differ ?
Stells [14]
Hi There!

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Hope This Helps :)
5 0
4 years ago
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