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2 years ago

A baseball pitcher throws a fastball with a 100 ns impulse. if he applied the force in 0. 15 seconds, what force did he apply?

Physics

1 answer:

Papessa [141]2 years ago

8 0

Answer:

The force he will apply is 666.667 N

Explanation:

The impulse is given as the product of Force and time:

Impulse (I) = F * t

As we are provided with the impulse and that is:

I = 100 ns and t = 0.15 s

So, required force is:

F = I/t

F = 100/0.15

F = 666.6667 N

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Air expands isentropically from 2.2 MPa and 77°C to 0.4 MPa. Calculate the ratio of the initial to the final speed of sound.

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Answer:

The ratio of initial to final speed of sound is given as 1.28.

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$\frac{T_2}{T_1}=(\frac{P_2}{P_1})^{\frac{k-1}{k}}$

Here

$P_1$ is the pressure at point 1 which is given as 2.2 MPa
$T_1$ is the temperature at point 1 which is given as 77 °C or 273+77=350K

$P_2$ is the pressure at point 1 which is given as 0.4 MPa
$T_2$ is the temperature at point 2 which is to be calculated
k is the ratio of specific heats given as 1.4

Substituting values in the equation

$\frac{T_2}{350}=(\frac{0.4}{2.2})^{\frac{1.4-1}{1.4}}\\\frac{T_2}{350}=(0.18)^{0.2857}\\T_2=(0.18)^{0.2857} \times 350 \\T_2=0.61266 \times 350\\T_2=214.43 K$