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emmasim [6.3K]
4 years ago
5

PLS HELP ME IVE BEEN TRYING

Mathematics
1 answer:
MrRissso [65]4 years ago
8 0

Answer:

try and let me know is it correct or not line A-4 lineB-8

Step-by-step explanation:

i also use mathswatch

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Erika has three pieces of ribbon. Each peice is 25 yards long.she needs to cut pieces that are 22inches long. What is the greate
sveticcg [70]
1 yard=36".
25 yeards = 25*36" = 900"
3 rolls = 3*900 =  2700"
Each piece must be 22" long, so the number of pieces
= 2700/22 = 122 pieces (2684") with 16" left over.

3 0
3 years ago
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A 10 ft fence is 8 in .long on the scale drawing. What is the scale drawing?
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To find scale we have to provide common unit, so inches.
10 foot = 120 inch becauyse 1 foot = 12 inch so 
10foot*12=120 ich
Now
8 inch in drawing is 120 in real, so the scale is 8:120
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3 years ago
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(3n³ - 5n + n²) - (-8n² + 3n³)
Dima020 [189]

-5n+9n^2

simplify expression ^

7 0
3 years ago
A circle has end points (-2,1) and (8,3).
Drupady [299]

Answer:

A) find its center  = (3, 2)

B) find the radius of the circle = √104

C) find the equation of the circle = x² + y² - 6x - 4y -91 = 0

Step-by-step explanation:

A)- The center must be the mid-points of (-2, 1) and (8, 3).

So, using the equation of mid-point,

h=\frac{x_{1}+x_{2}}{2}  and  k=\frac{y_{1}+y_{2}}{2}

Here, (x₁, y₁) = (-2, 1) and (x₂, y₂) = (8, 3)

Putting these value in above equation. We get,

h = 3 and k = 2

Thus, Center = (h, k) = (3, 2)

B)- For finding the radius we have to find the distance between center and any of the end point.

Thus using Distance Formula,

Distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

Radius =\sqrt{(8+2)^{2}+(3-1)^{2}}

⇒ Radius = √104 = 2√26

C)- The equation of circle is determined by formula:

(x-h)^{2}+(y - k)^{2} = r^{2}

where (h, k ) is center of circle and

r is the radius of circle.

⇒ (x - 3)² + (y - 2)² = 104

⇒ x² + y² - 6x - 4y -91 = 0

which is the required equation of the circle.

8 0
3 years ago
Write the expression as a single logarithm with a coefficient of 1.<br> 3 ln x − 8 ln y
viva [34]

Answer:

\ln(\frac{x^3}{y^8})

Step-by-step explanation:

3 \ln(x)-8\ln(y) is the given.

The instructions is to write as a single logarithm.

Let's use the power rule first:

\ln(x^3)-\ln(y^8)

Now we see the minus between the natural logs so we can use the quotient rule:

\ln(\frac{x^3}{y^8})

3 0
3 years ago
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