All categories

2 years ago

Twelve eggs cost $2.04 how much would 18 eggs cost?

Mathematics

2 answers:

marshall27 [118]2 years ago

4 0

Answer:

18 eggs would cost $3.06 :)

Step-by-step explanation:

quester [9]2 years ago

4 0

Answer:

If 12 eggs cost $2.04, then figure out how much 1 egg costs. You do that by dividing the total by the amount = 0.17. Take that number and multiply by how many eggs and you'll get the total which is $3.06

You might be interested in

The body temperatures of adults are normally distributed with a mean of 98.6degrees° F and a standard deviation of 0.60degrees°

Schach [20]

Answer:

97.72% probability that their mean body temperature is greater than 98.4degrees° F.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 98.6, \sigma = 0.6, n = 36, s = \frac{0.6}{\sqrt{36}} = 0.1$

If 36 adults are randomly selected, find the probability that their mean body temperature is greater than 98.4degrees° F.

This is 1 subtracted by the pvalue of Z when X = 98.4. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{98.4 - 98.6}{0.1}$

$Z = -2$

$Z = -2$ has a pvalue of 0.0228

1 - 0.0228 = 0.9772

97.72% probability that their mean body temperature is greater than 98.4degrees° F.

6 0

3 years ago

Please help it’s urgent! it’s tangent lines

sleet_krkn [62]

The answer should be 24, because you can mark out 5,and 10 cuz it doesn’t make since

3 0

2 years ago

Find the LCM of n^3 t^2 and nt^4. A) n 4t^6 B) n 3t^6 C) n 3t^4 D) nt^2

patriot [66]

Answer:

The correct option is C.

Step-by-step explanation:

The least common multiple (LCM) of any two numbers is the smallest number that they both divide evenly into.

The given terms are $n^3t^2$ and $nt^4$ .

The factored form of each term is

$n^3t^2=n\times n\times n\times t\times t$

$nt^4=n\times t\times t\times t\times t$

To find the LCM of given numbers, multiply all factors of both terms and common factors of both terms are multiplied once.

$LCM(n^3t^2,nt^4)=n\times n\times n\times t\times t\times t\times t$

$LCM(n^3t^2,nt^4)=n^3t^4$

The LCM of given terms is $n^3t^4$ . Therefore the correct option is C.

8 0

3 years ago

Read 2 more answers

Solve for x. 8.2x−6.2−7.2x=14 Enter your answer, as a decimal, in the box. x =

slavikrds [6]

Answer is: Solve for x by simplifying both sides of the equation, then isolating the variable.

x = 20.2

6 0

3 years ago

The distribution of the amount of money spent by students on textbooks in a semester is approximately normal in shape with a mea

zheka24 [161]

Answer:

$301 - $397

Step-by-step explanation:

Using the Empirical rule

1) 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ .

2)95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

3)99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ .

From the above question,

Mean = 349 , standard deviation = 24.

Confidence interval = 95%

Using 2)95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

μ – 2σ

= 349 - 2(24)

= 349 - 48

= 301

μ + 2σ

349 + 2(24)

= 349 + 48

= 397

Therefore, according to the standard deviation rule, approximately 95% of the students spent between $301 and $397 on textbooks in a semester.

8 0

3 years ago