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3 years ago

I need help with solving these math problem whoever gets them correct I mark brainliest!!!!

Mathematics

1 answer:

Margarita [4]3 years ago

7 0

Answer:

red side is a leg and should be labeled a or b, the pink side is a leg and should be labeled a or b, and the light blue side is the hypotenuse and should be labeled c.

3=a or b

4=a or b

5=c

Step-by-step explanation:

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Mia found the area of a polygon The area is 32 square cm.

solniwko [45]

Answer:

Only the isosceles trapezoid has an area of 32 cm².

Step-by-step explanation:

Let's calculate the area of each polygon.

For the two triangles we have:

$A_{t} = \frac{bh}{2} = \frac{2 cm*4 cm}{2} = 4 cm^{2}$

This polygon does not have an area of 32 cm².

For the rectangle we have:

$A_{r} = bh = 6 cm*4 cm = 24 cm^{2}$

This polygon does not have an area of 32 cm².

For the rectangle trapezoid we have:

$A_{rt} = A_{t} + A_{r} = (4 + 24) cm^{2} = 28 cm^{2}$

So, this polygon does not have an area of 32 cm².

Finally, for the isosceles trapezoid:

$A_{it} = A_{t}*2 + A_{r} = (4*2 + 24) cm^{2} = 32 cm^{2}$

This polygon does have an area of 32 cm².

Therefore, only the isosceles trapezoid has an area of 32 cm².

I hope it helps you!

8 0

3 years ago

Find the multiplicative inverse of 11/12

zzz [600]

Answer:

12/-11 is the multiplicative inverse of -11/12..

Step-by-step explanation:

8 0

3 years ago

What is the solution set of the quadratic inequality x^2+x-2>=0?

Firlakuza [10]

I think it’s gonna be the 3rd one

3 0

4 years ago

Please help assignment due very soon(no links or I will report you)

Dennis_Churaev [7]

Answer:

-2.35

Step-by-step explanation:

I'm not 100% Sure if that's correct but I'm pretty sure it is!

8 0

3 years ago

Read 2 more answers

What is the slope of the secant line? Thank you

Burka [1]

Answer:

Given that,

The function is,

$f(x)=1.2x^3-37x^2+265x+555$

To find: To find the slope of the secant line from x1=0 and x2=4

Explanation:

First we find the corresponding y values that is y1 and y2 for the given x1 and x2 respectively.

we get,

Whwn x1=0,

$y1=f(x1)=f(0)$

$f(0)=1.2(0)^3-37(0)^2+265(0)+555$ $f(0)=555$ $y1=555$

When x2=4, we get,

$f(4)=1.2(4)^3-37(4)^2+265(4)+555$ $f(4)=1099.8$

To find the slope of the line passing the points (0,555), (4,1099.8)

we know that,

Slope of the line passing through the points (x1,y1) and (x2,y2)

$m=\frac{y2-y1}{x2-x1}$

we get,

$m=\frac{1099.8-555}{4-0}$ $m=\frac{544.8}{4}$ $m=136.2$

Answer is:

Slope of the secant line from x1=0 and x2=4 is 136.2.

4 0

1 year ago