Answer:
Explanation:
Operation Address Hit? Read Value
Read 0x834 No Unknown
Write 0x836 Yes (not applicable)
Read 0xFFD Yes CO
Answer:
The two phases to the context of this discussion are listed follows.
Explanation:
- <u>Solution 1</u>: Delete 1 GB of current RAM as well as install another DIMM0 Chan A slot through one 2 GB of double-channel RAM. (thinkable unless the 2 GB RAM is provided by the motherboard in what seems like a DIMM0 Chan A slot)
- <u>Solution 2</u>: whether there's an unused or blank slot, perhaps one 1 GB dual-channel Ram could be mounted in some other slot at around the same speed or frequency.
It's quite safer to mount memory with appropriate frequencies across both situations.
Answer:
Pulling related code together in objects is Arrays
Helps programmers when they revisit code or are new to code-- Documentation
Explanation:
This is all I know
Answer:
<h3>Rules for Naming Variables</h3><h3>The first character must be a letter or an underscore (_). You can't use a number as the first character. The rest of the variable name can include any letter, any number, or the underscore. You can't use any other characters, including spaces, symbols, and punctuation marks.</h3>
<em><u>#</u></em><em><u>M</u></em><em><u>a</u></em><em><u>r</u></em><em><u>k</u></em><em><u>a</u></em><em><u>s</u></em><em><u>b</u></em><em><u>r</u></em><em><u>a</u></em><em><u>i</u></em><em><u>n</u></em><em><u>l</u></em><em><u>e</u></em><em><u>s</u></em><em><u>s</u></em><em><u>p</u></em><em><u>l</u></em><em><u>e</u></em><em><u>a</u></em><em><u>s</u></em><em><u>e</u></em><em><u>✅</u></em>
Answer:
// here is code in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n;
double average,sum=0,x;
cout<<"enter the Value of N:";
// read the value of N
cin>>n;
cout<<"enter "<<n<<" Numbers:";
// read n Numbers
for(int a=0;a<n;a++)
{
cin>>x;
// calculate total sum of all numbers
sum=sum+x;
}
// calculate average
average=sum/n;
// print average
cout<<"average of "<<n<<" Numbers is: "<<average<<endl;
return 0;
}
Explanation:
Read the total number from user i.e "n".Then read "n" numbers from user with for loop and sum them all.Find there average by dividing the sum with n.And print the average.
Output:
enter the Value of N:5
enter 5 Numbers:20.5 19.7 21.3 18.6 22.1
average of 5 Numbers is: 20.44
