Subnet 102.176.0.0/12
broadcast 102.191.255.255
lowest 102.176.0.1
highest 102.191.255.254
Answer:
Number of fragments is 3
Explanation:
The maximum size of data field in each fragment = 4468 - 20(IP Header)
= 4448 bytes
Hence, the number of required fragment = (10000 - 20)/4448
= 3
Fragment 1
Id = 218
offset = 0
total length = 4468 bytes
flag = 1
Fragment 2
Id = 218
offset = 556
total length = 4468 bytes
flag = 1
Fragment 3
Id = 218
offset = 1112
total length = 1144 bytes
flag = 0
<span>C) Always better to give your information and end on time.</span>
Answer:
D
Explanation:
The answer is D because if you're looking for lightweight materials, you'll be dealing with chemistry, and chemistry is sience.