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4 years ago

I have a series of 2 questions.

Mathematics

1 answer:

Margarita [4]4 years ago

3 0

1)
I:y=3x-4
II:9x-3y=14

substitute y into II:
9x-3*(3x-4)=14
9x-9x+12=14
12=14

this is obviously not equal so there is no solution, the lines are parallel

2)
I:y=4x+6
II:5x-y=6

substitute y into II:
5x-(4x+6)=6
5x-4x-6=6
x=12
substiute x into II:
5*12-y=6
-y=6-60
-y=-54
y=54

the solution is (12,54)

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A sheet of bad paper is cut into 12 equal parts. What percent of the whole is 3 parts?

11Alexandr11 [23.1K]

25%

Divide 12 by 3 and you'll get 4.
That means 1/4 or a quarter of the 12 is 3.
(Convert the fraction to its percentage form)
1/4 or 1 divided by 4 equals 0.25
Multiply 0.25 by 100 and you'll get 25%

3 0

3 years ago

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If x = 2 and y=-3, then -xy^2 = A) -36 B) 18 C) -12 D) - 18

Citrus2011 [14]

Answer:

-18

Step-by-step explanation:

-xy^2 =

Let x=2 and y = -3

-(2) (-3)^2

-2 (9)

-18

4 0

3 years ago

The following chart shows a store’s coat sales for two years.

STALIN [3.7K]

Answer:

Sales of trench coats increased 8.3 percentage points faster than total coat sales.

Step-by-step explanation:

2006:

top coats is 297,

parkas is 210,

jackets is 213,

raincoats is 137,

trench coats is 103

Total: $297+210+213+137+103=960$

2007:

topcoats is 223,

parkas is 210,

jackets is 285,

raincoats is 259,

trench coats is 127

Total: $223+210+285+259+127=1,104$

Percent increase in total sales:

$\dfrac{1,104-960}{960}\cdot 100\%=15\%$

Percent increase in sales of trench coats:

$\dfrac{127-103}{103}\cdot 100\%\approx 23.3\%$

Since $23.3\%-15\%=8.3\%,$ sales of trench coats increased 8.3 percentage points faster than total coat sales.

7 0

3 years ago

Read 2 more answers

One number is 2 more than 3 times another. their sum is 22. find the numbers. 8, 14

bija089 [108]

X + y = 22
x = 3y + 2

3y + 2 + y = 22
4y + 2 = 22
4y = 22 - 2
4y = 20
y = 20/4
y = 5

x = 3y + 2 = 3(5) + 2 = 15 + 2 = 17

ur numbers are 5 and 17

4 0

3 years ago

Read 2 more answers

~please only answer if you know for sure~

NARA [144]

JKL is similar to PQR

so they want PR

JKL is similar to PQR

So PR is similar to JL

And they also give us the sides KL and QR

JKL is similar to PQR

Both of those sides are similar, so we can form a proportion.

$\sf { \frac{PR}{JL} = \frac{QR}{KL} }$

Plug in the numbers:

$\sf { \frac{PR}{6} = \frac{15}{9} }$

Cross multiply:

$\sf{ PR \times 9 = 6 \times 15}$

Isolate PR

$\sf{ PR = \frac{6 \times 15}{9}}$

Simplify it

$\sf{ PR = 10}$

So your final answer is

$\boxed{\bf{10 centimeters}}$

6 0

4 years ago

Read 2 more answers