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3 years ago

I have a series of 2 questions.

Mathematics

1 answer:

Margarita [4]3 years ago

3 0

1)
I:y=3x-4
II:9x-3y=14

substitute y into II:
9x-3*(3x-4)=14
9x-9x+12=14
12=14

this is obviously not equal so there is no solution, the lines are parallel

2)
I:y=4x+6
II:5x-y=6

substitute y into II:
5x-(4x+6)=6
5x-4x-6=6
x=12
substiute x into II:
5*12-y=6
-y=6-60
-y=-54
y=54

the solution is (12,54)

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