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zloy xaker [14]

3 years ago

5

Please help with all!!

1 answer:

EastWind [94]3 years ago

4 0

Answer:

1. x=7

2. x= -12

3.x=12

4.x=9

5. x= -5

6. x=7

Step-by-step explanation:

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3 years ago

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Jewel is 7 years old and John is 16 years younger than Dave. One year ago, Dvae's age was twice the sum of Jewel's and John's ag

ivanzaharov [21]

Answer:

Jewel is 7 years old

John is 1 year old

Dave is 17 years old

Step-by-step explanation:

From the question we are told that:

Jewel age is $J=7 years$

John age $J'=(D-16)years$

Dave's age a Year ago

$D-1=2(J-1+J'-1)$

So that Dave.s age this Year could be

$D=2((J-1)+(J'-1))+1$

Simplifying Equation for Dave's age we have

$D=2((7)-1+(D-16)-1)+1$

$D=2(6+D-15)+1$

$D=2(D-9)+1$

$D=2D-18+1$

$D=17 Years$

Dave is 17 years old

Therefore

Johns age is

$J'=(D-16)$

$J'=17-16$

$J'=1year old$

John is 1 year old

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3 years ago

How do I do problems like this???!

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Answer:

Read it

Step-by-step explanation:

read it

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