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Serjik [45]
2 years ago
10

The length of one of the equal sides of an isosceles triangle is 4 cm. If its base is 2 cm, then what is its area?​

Mathematics
1 answer:
TEA [102]2 years ago
5 0

Answer:

A = 1/2bh

b = 2cm

h will be found using the side of the triangle with Pythagoras theorem

h² + 1² = 4²

h² = 15

h = √15 cm

then,

A = <u>2</u><u>*</u><u>√</u><u>1</u><u>5</u><u> </u>

2

A = √15cm²

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The left hand side of the equation contains proper fractions while the right hand side of the equation contains mixed fraction. The mixed fraction can be changed to improper fraction. 1 2/3 becomes 5/3

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