(a) there are 8C2 = 28 ways of picking 2 girls from 8
And there are 21C4 = 5985 ways of picking 4 boys
Required number of ways for 2g / 4b = 28 * 5985 = 167,580
(b) at least 2 girls means combinations of 2g/4b , 3g,3b , 4g/2b , 5g 1b or
6 girls.
2g/4b = 167,580 ways
3g/3b = 8C3 * 21C3 = 56 * 1330 = 74,480
4g/2b = 8C4* 21C2 = 70 * 210 = 14,700
5g 1b = 8C5* 21 = 56*21 = 1176
6 girls = 8C6 = 28
adding these up we get the answer to (b) which is 257,964
Answer:
33
Step-by-step explanation:
2x^2 +3y
Let x =3 and y=5
2 *(3)^2 +3(5)
We do exponents first
2 * 9 + 3(5)
Then multiply
18+ 15
Add
33
Hello!
P = 2,1cm + 2,1cm + 1cm + 3,3cm + 1cm => P = 4,2cm + 1cm + 3,3cm + 1cm => P = 5,2cm + 3,3cm + 1cm => P = 8,5cm + 1cm => P = 9,5cm
Answer: D. 9,5cm
Good luck! :)
Let's call the angles x and y. We know that supplementary angles must add to 180 degrees, so x+y=180.
Furthermore, we know that x is 75% more than 2y. We can write "75% more than" numerically as 1.75, so x = 1.75(2y).
We can simplify the second equation by multiplying 1.75 and 2 together to get x = 3.5y.
Now we can solve the system of equations by substitution by plugging 3.5y in for x in x+y=180.
(3.5y) + y = 180
Combine like terms.
4.5y = 180
Divide by 4.5
y = 40
Plug y = 40 in and solve for x.
x + 40 = 180
x = 140
The answer is 40 and 140. Hope this helps :)
