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Andrei [34K]
3 years ago
11

Which absolute value expression represents the distance between 3 and −5 on a number line?

Mathematics
1 answer:
lora16 [44]3 years ago
3 0

Answer:

B) To represent  the distance between 3 and −5 on a number line,  the correct expression is  I(3) - (-5)I .

Step-by-step explanation:

Here the point A is given as 3 on number line.

Point B is given as -5 on number line.

To find :  IA-BI

The distance between any two point A and B is given as IA-BI.

Now, to find the absolute value:

IA-BI = I  (3) - (-5)I

or, IA-BI = I (3) + 5I  = I8I

= 8 units

or, IA-BI = 8 units

Hence, on the number line, the distance between -5 and 3 is 8 units.

And, to represent  the distance between 3 and −5 on a number line,  the correct expression is  I(3) - (-5)I .

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Please answer this question​
max2010maxim [7]
<h3>━━━━━━❃━━━━━━</h3>

<h3>Part one :</h3>

As it is given :

Present age of mom : Present age of son = 6 : 1

Therefore let :

  • Mother's age be 6x

  • Son's age be x

<h3>Part two :</h3>

Ages after 10 year :

  • Mom's age = 6x + 10

  • Son's age = x + 10

<h3>Part three :</h3>

The ages after 10 years are given in rational of 8 : 3.

Which means :

Mom's age after 10 years : Son's age after 10 years = 8 :3.

Now :

\scriptsize \purple{ \boxed{ \scriptsize \dfrac{ \text{Mom's age after 10 years}}{ \text{son's age after 10 years}}= \dfrac{8}{3} }} \star

\\  \\

So :

\small\sf \dashrightarrow \dfrac{6x + 10}{x + 10} =  \sf \dfrac{8}{3}

\\  \\

\small\sf \dashrightarrow \dfrac{3(6x + 10)}{x + 10} =  \sf \dfrac{8}{1}

\\  \\

\small \sf \dashrightarrow \dfrac{18x +30}{x + 10} =  \sf \dfrac{8}{1}

\\  \\

\small\sf \dashrightarrow \dfrac{18x +30}{1} =  \sf \dfrac{8(x + 10)}{1}

\\  \\

\small \sf \dashrightarrow 18x +30=  \sf 8(x + 10)

\\  \\

\small\sf \dashrightarrow 18x +30=  \sf 8x + 80

\\  \\

\small\sf \dashrightarrow 18x - 8x +30=  \sf 80

\\  \\

\small \sf \dashrightarrow 10x +30=  \sf 80

\\  \\

\small \sf \dashrightarrow 10x =  \sf 80 - 30

\\  \\

\small \sf \dashrightarrow 10x =  \sf 50

\\  \\

\small \sf \dashrightarrow  \dfrac{10x}{10}  =  \sf  \dfrac{50}{10}

\\  \\

\small \sf \dashrightarrow  \dfrac{1\cancel0x}{1\cancel0}  =  \sf  \dfrac{5\cancel0}{1\cancel0}

\\  \\

\small\bf \dashrightarrow x = \pink 5

\\

<h3>Part four :</h3>

We know :

\footnotesize \hookrightarrow \sf Son's \: age = x

\footnotesize \hookrightarrow \sf Son's \: age =  \red{5 \: years}

\\  \\

\footnotesize \hookrightarrow \sf Mother's \: age  = 6x

\footnotesize\hookrightarrow \sf Mother's \: age  = 6 \times 5

\footnotesize \hookrightarrow \sf Mother's \: age  =  \bf \red{30 \: years}

<h3>━━━━━━❃━━━━━━</h3>

And all we are done ! ㋛

<h3>~\pmb{\cal W\frak{indy}M\frak{int}}༄</h3>
4 0
2 years ago
Please solve this with the steps.
bija089 [108]
Subtract 9/4 from both sides
3/4x=6 3/4
Multiply them by 4/3
X=9
5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=3%5En%5E%2B%5E1%2B9%2F3%5En%5E-%5E1%2B1" id="TexFormula1" title="3^n^+^1+9/3^n^-^1+1" alt="3^n
abruzzese [7]

Answer:

Hello,

Step-by-step explanation:

\dfrac{3^{n+1}+9}{3^{n-1}+1} \\\\=\dfrac{9*(3^{n-1}+1)}{3^{n-1}+1}\\\\=9\\

4 0
2 years ago
At a factory three workers produced 87, 93 and 102 units respectively in one day what is the average production in units of thes
slega [8]

Answer:

94

Step-by-step explanation:

Add units together. 87+93+102=282.

Divide total number by number of days. 282/3=94

6 0
2 years ago
The figure shows a kite inside a rectangle. Which expression represents the area of the shaded region? 2x2 4x2 6x2 8x2
notka56 [123]
The picture in the attached figure

we know that
area of the <span>the shaded region=area of rectangle -area of a kite

area of rectangle=(3x+x)*(x+x)----> 4x*2x---> 8x</span>²

area of a kite=(1/2)*[d1*d2]
where d1 and d2 are the diagonals
d1=4x
d2=2x
so
area of a kite=(1/2)*[4x*2x]----> 4x²

area of the the shaded region=8x²-4x²-----> 4x²

the answer is 
4x²

5 0
3 years ago
Read 2 more answers
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