Answer:
yes
Step-by-step explanation:
To determine if the point is a solution, substitute the coordinates into the left side of the inequality, evaluate and compare with right side.
- 8(3) - 2(2) = - 24 - 4 = - 28 < 6
Thus (3, 2) is a solution
Answer:
-68 is your answer
Step-by-step explanation:
Remember to follow PEMDAS (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction)
First, solve each parenthesis
(-21 x 3) = -63
(15/-3) = -5
Next, add
(-63) + (-5) = -63 - 5 = -68
-68 is your answer
~
The number is increasing by 2 every time.
78 x 2 = 156
-4 + 156 = 152
The 78th term is 152
Answer:
a=5your answer right answer right answer
Answer:
0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.
The sketch is drawn at the end.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 0°C and a standard deviation of 1.00°C.
This means that
Find the probability that a randomly selected thermometer reads between −2.23 and −1.69
This is the p-value of Z when X = -1.69 subtracted by the p-value of Z when X = -2.23.
X = -1.69
has a p-value of 0.0455
X = -2.23
has a p-value of 0.0129
0.0455 - 0.0129 = 0.0326
0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.
Sketch: