The balanced equation for the above neutralisation reaction is as follows; 2KOH + H₂SO₄ --> K₂SO₄ + 2H₂O stoichiometry of KOH to H₂SO₄ is 2:1 neutralisation is the reaction between H⁺ ions and OH⁻ ions to form water which is neutral number of KOH moles - 1.56 mol 2 mol of KOH require 1 mol of H₂SO₄ for neutralisation therefore 1.56 mol of KOH require - 1/2 x 1.56 mol = 0.78 mol 0.78 mol of H₂SO₄ are required for neutralisation
