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disa [49]
3 years ago
10

How many moles of h2so4 are needed to neutralize 1.56 moles of koh?

Chemistry
1 answer:
Firlakuza [10]3 years ago
5 0
The balanced equation for the above neutralisation reaction is as follows;
2KOH + H₂SO₄ --> K₂SO₄ + 2H₂O
stoichiometry of KOH to H₂SO₄ is 2:1
neutralisation is the reaction between H⁺ ions and OH⁻ ions to form water which is neutral
number of KOH moles - 1.56 mol 
2 mol of KOH require 1 mol of H₂SO₄ for neutralisation
therefore 1.56 mol of KOH require - 1/2 x 1.56 mol = 0.78 mol 
0.78 mol of H₂SO₄ are required for neutralisation  
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Read 2 more answers
How many moles of co2 are there in a 50.0 dm3 sample of the gas at a pressure of 100.0 kpa and a temperature of 50°c?
Rudiy27

Answer:

  • 609 mol

Explanation:

<u>1) Data:</u>

a) n = ?

b) V = 50.0 dm³ = 50.0 liter

c) p = 100.0 kPa

d) T = 50 °C

<u>2) Physical law:</u>

  • Ideal gas law: pV = nRT,

<u>3) Constants:</u>

  • R = 0.08206 atm-liter / K-mol

<u>4) Unit conversions:</u>

  • T = 50 + 273.15 K = 323.15 K

  • P = 100.0 kPa × (1 amt  /101,325 kPa) = 0.9869 atm

<u>5) Solution:</u>

  • pV = nRT ⇒ n = pV / (RT)

  • n = 0.9869 atm × 50.0 liter / (0.08206 atm-liter /K-mol × 323.15 K)

  • n = 609 mol ← answer
7 0
3 years ago
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