1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
My name is Ann [436]
3 years ago
14

A brick has a mass of and the Earth has a mass of . Use this information to answer the questions below. Be sure your answers hav

e the correct number of significant digits. What is the mass of 1 mole of bricks? Round your answer to 2 significant digits. How many moles of bricks have a mass equal to the mass of the Earth? Round your answer to 2 significant digits.
Chemistry
1 answer:
weeeeeb [17]3 years ago
5 0

The given question is incomplete. The complete question is:

A brick has a mass of 4.0 kg and the earth has a mass of 6.0\times 10^{27}g Use this information to answer the questions below. Be sure your answers have the correct number of significant digits. What is the mass of 1 mole of bricks? Round your answer to 2 significant digits. How many moles of bricks have a mass equal to the mass of the Earth? Round your answer to 2 significant digits.

Answer: The mass of 1 mole of bricks is 2.4\times 10^{27}g

2.5 moles of bricks have a mass equal to the mass of the Earth

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

Mass of 1 brick = 4.0 kg = 4000 g     (1kg=1000g)

Thus mass of 1 mole of brick or 6.023\times 10^{23} bricks will be = \frac{4000g}{1}\times 6.023\times 10^{23}=2.4\times 10^{27}g

The mass of 1 mole of bricks is 2.4\times 10^{27}g

Now 2.4\times 10^{27}g will correspond to = 1 mole of bricks

6.0\times 10^{27}g will correspond to =\frac{1}{2.4\times 10^{27}}\times 6.0\times 10^{27}=2.5moles

2.5 moles of bricks have a mass equal to the mass of the Earth

You might be interested in
Starting with 9.3 moles of O2, how many moles of H2S will be needed and how many moles of SO2 will be produced in the following
tensa zangetsu [6.8K]

<u>Answer:</u> The amount of hydrogen sulfide needed is 6.2 moles and amount of sulfur dioxide gas produced is 6.2 moles

<u>Explanation:</u>

We are given:

Moles of oxygen gas = 9.3 moles

The chemical equation for the reaction of oxygen gas and hydrogen sulfide follows:

2H_2S+3O_2\rightarrow 2SO_2+2H_2O

<u>For hydrogen sulfide:</u>

By Stoichiometry of the reaction:

3 moles of oxygen gas reacts with 2 moles of hydrogen sulfide

So, 9.3 moles of oxygen gas will react with = \frac{2}{3}\times 9.3=6.2mol of hydrogen sulfide

<u>For sulfur dioxide:</u>

By Stoichiometry of the reaction:

3 moles of oxygen gas produces 2 moles of sulfur dioxide

So, 9.3 moles of oxygen gas will produce = \frac{2}{3}\times 9.3=6.2mol of sulfur dioxide

Hence, the amount of hydrogen sulfide needed is 6.2 moles and amount of sulfur dioxide gas produced is 6.2 moles

7 0
3 years ago
The equation represents the decomposition of a generic diatomic element in its standard state. 12X2(g)⟶X(g) Assume that the stan
BlackZzzverrR [31]

Answer:

The equilibrium constant at 2000 K is 0.7139

The equilibrium constant at 3000 K is 8.306

ΔH = 122.2 kJ/mol

Explanation:

Step 1: Data given

the standard molar Gibbs energy of formation of X(g) is 5.61 kJ/mol at 2000 K

the standard molar Gibbs energy of formation of X(g) is -52.80 kJ/mol at 3000 K

Step 2: The equation

1/2X2(g)⟶X(g)

Step 3: Determine K at 2000 K

ΔG = -RT ln K

⇒R = 8.314 J/mol *K

⇒T = 2000 K

⇒K is the equilibrium constant

5610 J/mol = -8.314 J/molK * 2000 * ln K

ln K = -0.337

K = e^-0.337

K = 0.7139

The equilibrium constant at 2000 K is 0.7139

Step 4: Determine K at 3000 K

ΔG = -RT ln K

⇒R = 8.314 J/mol *K

⇒T = 3000 K

⇒K is the equilibrium constant

-52800 J/mol = -8.314 J/molK * 3000 * ln K

ln K = 2.117

K = e^2.117

K = 8.306

The equilibrium constant at 3000 K is 8.306

Step 5: Determine the value of ΔH∘rxn

ln K2/K1 = -ΔH/r * (1/T2 - 1/T1)

ln 8.306 /0.713 = -ΔH/8.314 * (1/3000 - 1/2000)

2.455 = -ΔH/8.314 * (3.33*10^-4 - 0.0005)

2.455 = -ΔH/8.314 * (-1.67*10^-4)

-14700= -ΔH/8.314

-ΔH = -122200 J/mol

ΔH = 122.2 kJ/mol

6 0
4 years ago
What ionic are compounds used in our daily life?
Gemiola [76]

Answer:

Explanation:

NaCl sodium Chloride as ordinary salt

Naf sodium fluoride is used in toothpaste which we use every day

4 0
3 years ago
Conversion .5 km to inches
natta225 [31]
19685 because 1 km in inches is 39370 approximately so you just have to cut it in half
5 0
3 years ago
Read 2 more answers
Heat will continue to move until the objects or areas have reached the same ______.
ANEK [815]

Answer: Thermal Equilibrium

Explanation:

3 0
3 years ago
Read 2 more answers
Other questions:
  • In the reaction of sodium with oxygen____.
    8·2 answers
  • Identify the base-conjugate acid pair in this balanced equation:<br><br> NH3 + HNO3 → NH4+ + NO3−
    7·1 answer
  • How many moles of gas are in 4.4 mL at 1.2 atm?
    6·1 answer
  • A certain material has a density of 0.2 g/ml is this material good for building a bridge or for making cushions for a couch
    11·1 answer
  • A certain reaction is exothermic in the forward direction and has fewer molecules of gas on the product side. Which set of actio
    8·1 answer
  • How many mols of silver nitrate should be used to create 0.250 L of a 0.500 M solution?
    10·1 answer
  • carbon has an average atomic mass of 12.011 amu (as given on the periodic table). Which isotope of carbon do you think is more a
    7·1 answer
  • Which of the following matches a ratio of 2:3
    8·1 answer
  • 5. Determine if a precipitation reaction occurs between aqueous silver nitrate and aqueous calcium chloride. If a
    15·1 answer
  • Just need question 3 answered!!
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!