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My name is Ann [436]
2 years ago
14

A brick has a mass of and the Earth has a mass of . Use this information to answer the questions below. Be sure your answers hav

e the correct number of significant digits. What is the mass of 1 mole of bricks? Round your answer to 2 significant digits. How many moles of bricks have a mass equal to the mass of the Earth? Round your answer to 2 significant digits.
Chemistry
1 answer:
weeeeeb [17]2 years ago
5 0

The given question is incomplete. The complete question is:

A brick has a mass of 4.0 kg and the earth has a mass of 6.0\times 10^{27}g Use this information to answer the questions below. Be sure your answers have the correct number of significant digits. What is the mass of 1 mole of bricks? Round your answer to 2 significant digits. How many moles of bricks have a mass equal to the mass of the Earth? Round your answer to 2 significant digits.

Answer: The mass of 1 mole of bricks is 2.4\times 10^{27}g

2.5 moles of bricks have a mass equal to the mass of the Earth

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

Mass of 1 brick = 4.0 kg = 4000 g     (1kg=1000g)

Thus mass of 1 mole of brick or 6.023\times 10^{23} bricks will be = \frac{4000g}{1}\times 6.023\times 10^{23}=2.4\times 10^{27}g

The mass of 1 mole of bricks is 2.4\times 10^{27}g

Now 2.4\times 10^{27}g will correspond to = 1 mole of bricks

6.0\times 10^{27}g will correspond to =\frac{1}{2.4\times 10^{27}}\times 6.0\times 10^{27}=2.5moles

2.5 moles of bricks have a mass equal to the mass of the Earth

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An element X combines with oxygen to form a compound of formula XO2. If 24.0 grams of element X combines with exactly 16.0 grams
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Answer:

atomic mass of X is 48.0 amu

Explanation:

Let y be the atomic mass of X

Molar mass of O_2 is = 2×16 = 32 g / mol

X + O2 -----> XO_2

According to the equation ,

y g of X reacts with 32 g of O_2

24 g of X reacts with Z g of O_2

Z = ( 32×24) / y

But given that 24.0 g of X exactly reacts with 16.0 g of O_2

So Z = 16.0

⇒ (32×24) / y = 16.0

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Consider the molecule BF3. (a) What is the electron config- uration of an isolated B atom? (b) What is the electron con- figurat
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For the given molecule, we are asked to give-

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as atomic number of B is 5

electronic configuration will be [He] 2s² 2p¹

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electronic configuration will be  [He] 2s² 2p5

  • Hybrid orbitals should be constructed on the B atom to make the B–F bonds in Boron tri flouride will be sp2.

as the one s and two of p orbital from the valance shell will hybridised to make 3 hybrid orbital of B resulting in 3 B-F bonds.

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Crystals structures can also be seen when two elements combines together and the perfect example is Al₂O₃ which is given in the question above. Just like it is given in the question above, the kind of arrangement in the crystal structure for Al₂O₃ is called HCP which stands for Hexagonally Closed Pack.

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