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rusak2 [61]
3 years ago
12

Which serves as evidence for a scientific claim?

Chemistry
2 answers:
diamong [38]3 years ago
8 0

Answer: Option (c) is the correct answer.

Explanation:

A scientific claim is the scientific data that is appropriate and the enough to support the claim.

A scientific claim involves controlled experiments which are related to the claim and on the basis on these experiments further conclusion can be drawn which supports the claim.

Thus, we can conclude that controlled experiments serves as evidence for a scientific claim.

Serggg [28]3 years ago
5 0
Controlled experiments 
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33. You are given a flask that contains sea water that has been contaminated with oil. Some sand is
MaRussiya [10]

Answer:

By Filtration , Distillation , and then using a Separating Funnel

Explanation:

1) Use filtration to separate sand from sea water. Sand remains on the filter paper and the rest of salty water with oil is collected in the flask.'

2) Use distillation to separate salt from the water and oil collected in the flask. Water boils at 100°C , salt doesn't. So evaporate the water an then condense it in another container.

3) Use Separating Funnel to separate oil and water as both have different density.

3 0
4 years ago
The formula for a buffer solution contains 1.24% w/v of boric acid. How many milliliters of a 5% w/v boric acid solution should
Yanka [14]

Answer:

248 mL of 5% w/v boric acid solution should be used to obtain the solution needed.

 

Explanation:

We can calculate the volume of the 5% w/v boric acid solution needed to prepare the buffer solution 1.24% w/v using the following equation:

C_{i}V_{i} = C_{f}V_{f}

Where:

C_{i}: is the concentration of the initial solution = 5% w/v

C_{f}: is the concentration of the final solution = 1.24% w/v

V_{i}: is the volume of the initial solution =?

V_{f}: is the volume of the final solution = 1 L

Hence, the volume of the 5% solution is:

V_{i} = \frac{C_{f}V_{f}}{C_{i}} = \frac{1.24 \%*1 L}{5 \%} = 0.248 L = 248 mL

Therefore, 248 mL of 5% w/v boric acid solution should be used to obtain the solution needed.

I hope it helps you!                  

6 0
3 years ago
Calculate the de Broglie wavelength of a shotgun
snow_lady [41]

Answer : The de Broglie wavelength will be 3.68\times 10^{-33}m

Solution :

The formula used for de Broglie wavelength is:

\lambda=\frac{h}{mv} ..........(1)

where,

\lambda = wavelength  = ?

h = Planck's constant  = 6.626\times 10^{-34}Js

m = mass  = 1.2 g = 0.0012 kg

Conversion used : 1 kg = 1000 g

v = velocity  = 150 m/s

Now put all the given values in equation 1, we get:

\lambda=\frac{6.626\times 10^{-34}Js}{(0.0012kg)\times (150m/s)}

\lambda=3.68\times 10^{-33}m

Therefore, the de Broglie wavelength will be 3.68\times 10^{-33}m

3 0
3 years ago
One liter of air contains about 0.21 L of oxygen. When filled, the human lungs hold about 6.0 L of air. How much oxygen is in th
Pie
Simple 6L of air times the .21L of O2 = 1.26

3 0
3 years ago
What does the graph of data from the Moana Loa lab indicate about the level of CO2 in the atmosphere in 1960 compared to the pre
lawyer [7]

I don't know the answer honestly

Explanation:

cuz like why

3 0
3 years ago
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