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3 years ago

Determine the possible side lengths of the third side of a triangle with known side lengths of 5 and 8.

Mathematics

2 answers:

andre [41]3 years ago

8 0

Answer:

Step-by-step explanation:

8 times 5=40

Varvara68 [4.7K]3 years ago

3 0

Answer:

Answer:

3 < c < 13

Step-by-step explanation:

A triangle is known to have 3 sides: Side a, Side b and Side c.

For a triangle, one of the three sides is longer than the other two sides. (The only exception is when we are told specifically that a triangle is an equilateral triangle, where all the 3 sides are equal to each other).

To solve the above question, we would be using the Triangle Inequality Theorem.

The Triangle Inequality Theorem states that the summation or addition of the lengths of any two sides of a triangle is greater than the length of the third side.

Side a + Side b > Side c

Side a + Side c > Side b

Side b + Side c > Side a

For the above question, we have 2 possible side lengths for the third side of the triangle. We are given in the above question,

side (a) = 5

side (b) = 8

Let's represent the third side as c

To solve for the above question,we would be having the following Inequality.

= b - a < c < b + a

= 8 - 5 < c < 8 + 5

= 3 < c < 13

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Answer:

$y=\frac{4}{3}-\frac{x}{3e}$

Step-by-step explanation:

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y-y₁=m(x-x₁)

at (e,1)

$y-1=-\frac{1}{3e}(x-e)\\\\y=1-\frac{1}{3e}(x-e)\\\\y=1+\frac{1}{3}-\frac{x}{3e}\\\\y=\frac{4}{3}-\frac{x}{3e}\\$

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4 years ago

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Dmitry_Shevchenko [17]

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3 years ago

Read 2 more answers

How to solve question 19 thanks

miskamm [114]

Let $X$ be the random variable for the weight of any given can, and let $\mu$ and $\sigma$ be the mean and standard deviation, respectively, for the distribution of $X$ .

You have

$\begin{cases}\mathbb P(X377)=0.025\end{cases}$

Recall that for any normal distribution, approximately 99.7% of it lies within three standard deviations of the mean, i.e. $\mathbb P(\mu-3\sigma$ . This means 0.3% must lie outside this range, $\mathbb P(X\mu+3\sigma)=0.003$ . Because the distribution is symmetric, it follows that $\mathbb P(X$ .

Also recall that for any normal distribution, about 95% of it falls within two standard deviations of the mean, so $\mathbb P(\mu-2\sigma$ , which means 5% falls outside, and by symmetry, $\mathbb P(X>\mu+2\sigma)=0.025$ .

Together this means

$\begin{cases}\mu-3\sigma=347\\\mu+2\sigma=377\end{cases}$

Solving for the mean and standard deviation gives $\mu=365$ and $\sigma=6$ .

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