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4 years ago

Isnt 5.5 bigger 5???

Mathematics

2 answers:

Tamiku [17]4 years ago

8 0

Yes 5.5 is bigger then5

Nitella [24]4 years ago

7 0

Yes, 5.5 is bigger than 5

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How many permutations exist of the letters a, b, c, d taken two at a time?

Fittoniya [83]

The number of permutations of the 4 different letters, taken two at a time, is given by:
$4P2=\frac{4!}{2!}=12$

3 0

4 years ago

Read 2 more answers

Your friend claims that when a polynomial function has a leading coeffcient of 1 and the coefficients are all integers , every p

sammy [17]

Using the rational root theorem, it is found that your friend is correct.

<h3>What is the rational root theorem?</h3>

It is a theorem that states that for a polynomial with integer coefficients, with q being the factors of the leading coefficient and p being the factors of the constant, every <u>possible rational root</u> is the format $\frac{p}{q}$ .

In this problem:

The leading coefficient is 1, hence it's only factor is $q = 1$ , thus guaranteeing that every possible rational zero is an integer, which means that your friend is correct.

To learn more about the rational root theorem, you can take a look at brainly.com/question/10937559

8 0

3 years ago

Badal has 120 cm 3 of water. He wants to pour it into a rectangular vase that is 4 cm high, 4 cm wide, and 5 cm long. Can he pou

Anestetic [448]

Answer:

volume= 4×4×5

Therefore he can't pour all the water into the vase because the amount of water is 120cm³ whilst the vase is 80. An amount of water as that can't fill the vase

6 0

3 years ago

After graphing 4x-2y=5 and y=x, in how many points do they intersect

Angelina_Jolie [31]

Answer:

1 at (2.5, 2.5)

Step-by-step explanation:

you can try graphing it on desmo

3 0

4 years ago

Match the expressions with their equivalent simplified expressions.

Tasya [4]

Answer:

$\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}$

Step-by-step explanation:

$\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}} =\sqrt[4]{\frac{(2^4)(x^{6-2})(y^{4-8})}{(3^4)}} =\sqrt[4]{\frac{2^4x^4y^{-4}}{3^4}} =\frac{2xy^{-1}}{3}=\frac{2x}{3y}$

$\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} =\sqrt[4]{\frac{(3^4)(x^{2-6})(y^{10-6})}{(2^4)}} =\sqrt[4]{\frac{3^4x^{-4}y^{4}}{2^4}} =\frac{3x^{-1}y^1}{3}=\frac{3y}{2x}$

$\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}} =\sqrt[3]{\frac{(4^3)(x^{8-2})(y^{7-10})}{(5^3)}} =\sqrt[3]{\frac{4^3x^6y^{-3}}{5^3}} =\frac{4x^2y^{-1}}{5}=\frac{4x^2}{5y}$

$\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}} =\sqrt[5]{\frac{(3^5)(x^{17-7})(y^{16-21})}{(2^5)}} =\sqrt[5]{\frac{3^5x^{10}y^{-5}}{2^5}} =\frac{3x^2y^{-1}}{2}=\frac{3x^2}{2y}$

$\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} =\sqrt[5]{\frac{(2^5)(x^{12-7})(y^{15-10})}{(3^5)}} =\sqrt[5]{\frac{2^5x^{5}y^{5}}{3^5}} =\frac{2x^1y^{1}}{3}=\frac{2xy}{3}$

$\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}} =\sqrt[4]{\frac{(2^4)(x^{10-2})(y^{9-17})}{(4^4)}} =\sqrt[4]{\frac{2^4x^{8}y^{-8}}{4^4}} =\frac{2x^{1}y^{-1}}{4}=\frac{x}{2y}$

Thus,

3 0

3 years ago