Answer:
Average speed = 8.8 m/s
Average velocity = 8.8 m/s
Explanation:
From the question,
Avearge speed = 2πr/t................ Equation 1
Where r = 14 m, t = 10 s
Constant π = 22/7
Substitute this value into equation 1
Average speed = 2(22/7)(14)/10
Avearge speed = 8.8 m/s.
For a body moving in circular motion, The average speed and average velocity are equal.
Hence,
Average speed = 8.8 m/s
Average velocity = 8.8 m/s
Answer:
Find a recipient that you can put the object completely inside, and fill this recipient with water. After, you put the irregular solid you want to measure the volume inside, and the water will spill out the recipient. So you take the water that spilled out and uses a graduated recipient to measure the volume of water. The volume of the solid will be exactly the same volume of water that spilled of the first recipient
Answer:
It requires more tension to pull up the track
Explanation:
Net force must be zero to maintain constant velocity.
Weight force will always be pointed down the slope. Call it W
Friction force (Call it Ff) will be down slope when movement is up slope.
Friction force will be up slope when movement is down slope.
W and Ff are always positive numbers
Call the pulling force T
If Up slope is considered the positive direction
Moving up slope
Tu - Ff - W = 0
Tu = Ff + W
Moving down slope
Td + W - Ff = 0
Td = Ff - W
Ff + W > Ff - W therefore Tu > Td
<span>stuntman's vertical velocity is
vy= 6 sin 15=1.55m/s.
Height that he goes up is,
vertical kinetic energy = mgh
1/2 v² = gh, h=v²/(2g)=0.12 m.
time wanted to go up= vy/9.8=0.16s, Time to fall through a height
0.12+2.9=3.02m is
t=sqrt(3.02*2/9.8)=0.78 s
Total time needed to go up and down is 0.78+0.16=0.94 s.
to calculate the horizontal range,
Horizontal velocity = 6 cos 15=5.8 m/s.
Distance which he can cover is
5.8*0.94=5.44 m.
If the distance between the two building is less than 5.44 m then he will be safe and he can jump that distance.</span>