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rusak2 [61]
3 years ago
14

In an action movie, a stuntman leaps from the top of one building to the top of another building 5.2 m away. After a running sta

rt, he leaps at a velocity of 6.0 m/s at an angle of 15° above horizontal. Will he make it to the other roof, which is 2.9 m shorter than the building he jumps from?
Physics
1 answer:
Ksenya-84 [330]3 years ago
8 0
<span>stuntman's vertical velocity is vy= 6 sin 15=1.55m/s. Height that he goes up is, vertical kinetic energy = mgh 1/2 v² = gh, h=v²/(2g)=0.12 m. time wanted to go up= vy/9.8=0.16s, Time to fall through a height 0.12+2.9=3.02m is t=sqrt(3.02*2/9.8)=0.78 s Total time needed to go up and down is 0.78+0.16=0.94 s. to calculate the horizontal range, Horizontal velocity = 6 cos 15=5.8 m/s. Distance which he can cover is 5.8*0.94=5.44 m. If the distance between the two building is less than 5.44 m then he will be safe and he can jump that distance.</span>
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1 year ago
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3 years ago
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8 0
3 years ago
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Answer:

<em><u>1)A)</u></em>

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4 0
3 years ago
A current of 9 A flows through an electric device with a resistance of 43 Ω. What must be the applied voltage in this particular
NeTakaya
Answer:
387 volts

Explanation:
Ohm's law is used to relate voltage, current and resistance.
The formula is as follows:V = I * R
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In the given, we have:
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Substitute with the givens in the above formula to get the voltage as follows:
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Hope this helps :)
4 0
3 years ago
Read 2 more answers
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