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rusak2 [61]
3 years ago
14

In an action movie, a stuntman leaps from the top of one building to the top of another building 5.2 m away. After a running sta

rt, he leaps at a velocity of 6.0 m/s at an angle of 15° above horizontal. Will he make it to the other roof, which is 2.9 m shorter than the building he jumps from?
Physics
1 answer:
Ksenya-84 [330]3 years ago
8 0
<span>stuntman's vertical velocity is vy= 6 sin 15=1.55m/s. Height that he goes up is, vertical kinetic energy = mgh 1/2 v² = gh, h=v²/(2g)=0.12 m. time wanted to go up= vy/9.8=0.16s, Time to fall through a height 0.12+2.9=3.02m is t=sqrt(3.02*2/9.8)=0.78 s Total time needed to go up and down is 0.78+0.16=0.94 s. to calculate the horizontal range, Horizontal velocity = 6 cos 15=5.8 m/s. Distance which he can cover is 5.8*0.94=5.44 m. If the distance between the two building is less than 5.44 m then he will be safe and he can jump that distance.</span>
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Nadusha1986 [10]

The statement that is true regarding a distance vs. time graph is option A: The graph should show distance on the vertical axis.

<h3>Where is the plot of distance?</h3>

How far an object has come in a certain amount of time is displayed on a distance-time graph. Time is represented on the X-axis and Distance is plotted on the Y-axis (left) (bottom).

On a distance-time graph, an object's motion is indicated by a sloping line. The slope or gradient of the line in a distance-time graph is equal to the object's speed. The object is travelling more quickly the steeper the line is (and the bigger the gradient).

Note that the distance-time graph shows the relationship between distance and time by plotting distance on the y-axis and time on the x-axis.

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6 0
11 months ago
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KengaRu [80]

Answer:

20 meters.

Explanation:

In the graph, the x-axis (the horizontal axis) represents the time, while the y-axis (the vertical axis) represents the distance.

If we want to find the distance covered in the first T seconds, you need to find the value T in the horizontal axis.

Once you find it, we draw a vertical line, in the point where this vertical line touches the graph, we now draw a horizontal line. This horizontal line will intersect the y-axis in a given value. That value is the total distance travelled by the time T.

In this case, we want to find the total distance that David ran in the first 4 seconds.

Then we need to find the value 4 seconds in the horizontal axis. Now we perform the above steps, and we will find that the correspondent y-value is 20.

This means that in the first 4 seconds, David ran a distance of 20 meters.

6 0
2 years ago
While strolling downtown on a Saturday afternoon, you stumble across an old car show. As you are walking along an alley toward a
snow_tiger [21]

Answer:

1.44 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v=u+at\\\Rightarrow v=0+a\times 5\\\Rightarrow v=5a

This velocity will be the initial velocity of the car when it passes through the first building

s=ut+\frac{1}{2}at^2\\\Rightarrow 3=5a\times 0.4+\frac{1}{2}\times a\times 0.4^2\\\Rightarrow a=1.44\ m/s^2

The acceleration of the car is 1.44 m/s²

7 0
3 years ago
Make a graph of the data. You may use a graphing program. Think about what data should be on the y-axis and the x-axis. Be sure
Lynna [10]

Answer:

yes it was a constant speed and the car traveled 10 meters in 20 seconds.

Explanation:

8 0
3 years ago
The power in an electric circuit varies inversely with the resistance. If the power is 2,200 watts when the resistance is 25 ohm
valentinak56 [21]

Answer:

The value of resistance when power is 1100 watts = R_{2} = 50 ohms

Explanation:

Power P_{1} = 2200 Watts

Resistance R_{1} = 25 ohms

Power P_{2} = 1100 Watts

Resistance R_{2} = we have to calculate

Given that the power in an electric circuit varies inversely with the resistance

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⇒ \frac{P_{2} }{P_{1} } = \frac{R_{1} }{R_{2} }

⇒ \frac{1100}{2200} = \frac{25}{R_{2} }

⇒ R_{2} = 50 ohms

This is the value of resistance when power is 1100 watts.

6 0
3 years ago
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