Answer:
The specific heat for the metal is 0.466 J/g°C.
Explanation:
Given,
Q = 1120 Joules
mass = 12 grams
T₁ = 100°C
T₂ = 300°C
The specific heat for the metal can be calculated by using the formula
Q = (mass) (ΔT) (Cp)
ΔT = T₂ - T₁ = 300°C - 100°C = 200°C
Substituting values,
1120 = (12)(200)(Cp)
Cp = 0.466 J/g°C.
Therefore, specific heat of the metal is 0.466 J/g°C.
Answer:
P =105.44 W
Explanation:
Given that
D= 10 cm ,L= 60 cm
d= 0.1 cm ,B= 6.4 mT
ρ= 1.7 x 10⁻⁸ Ω · m
The number of turns N
N= L/d
N= 60/0.1 = 600 turns
Length of wire
Lc= πDN
Lc= 3.14 x 0.1 x 600
Lc=188.4 m
The magnetic filed given as
Now by putting the values
I=5.09 A
The resistance R given as
R=4.07 Ω
Power P
p =I²R
P= 5.09² x 4.07 W
P =105.44 W
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Explanation:
We will calculate the gravitational potential energy as follows.
=
= 1164000 J
or, = 1164 kJ (as 1 kJ = 1000 J)
Now, we will calculate the change in potential energy as follows.
=
=
= -873000 J
or, = -873 kJ
Thus, we can conclude that change in gravitational potential energy is -873 kJ.